run.bat file

Posted on 2003-12-07
Last Modified: 2010-03-31
I am having weird error. I am passing two args when I run this program.
args[1] is:
However, when I put this url in run.bat file like this:

java <program>  <path>

args[1] comes into main without "%7", and that is why my program doesn't work.
Another word, System.out.println("args[1] " + args[1] ); just print
Of course, run.bat file is excutable file.

Why is that?

  public static void main(String[] args) throws CrawlerException {

    //final String LINE_SEPARATOR = System.getProperty("line.separator");
    //StringBuffer buffy = new StringBuffer("");

      System.out.println("args[1] " + args[1] );
      URL url = new URL(args[1]);
Question by:dkim18
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
  • 2
LVL 24

Assisted Solution

shivsa earned 100 total points
ID: 9894681
could u try to use escape before the special charactor.

Expert Comment

ID: 9894699
What platform are you running? For Win it works fine without escaping...

Assisted Solution

vk33 earned 25 total points
ID: 9894807
heh, I'm half asleep... What other platform could require *.bat files... :)
Really I don't know, I tried your code for one argument (arg[0]), it works allright without escaping '%' character. Maybe shivsa is right and you should escape it because your Windows parses it as a start of environment variable reference. But again on the WinXP of mine it worked alright.

Good luck!
Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!


Accepted Solution

Breadstick earned 125 total points
ID: 9894847
In batch files, when you use a percent sign followed by a number, the percent and number are replaced with that argument that was passed to the batch file.  So if in a batch called hello.bat  I were to write:
echo %1
and then to execute it i typed:
hello.bat HelloWorld
then the program would echo HelloWorld

Your batch file is replacing %7 with the 7th argument that you passed the batch file.  Because you didn't pass it seven arguments, it's replacing it with nothing.

Expert Comment

ID: 9894867
To escape the percent in a batch file, you type %%.  Just the percent character twice.
LVL 24

Expert Comment

ID: 9894868
and thats why i said to escape since windows should not take it as a its own operator and treat it as a special character.

Expert Comment

ID: 9894883
Ah, yeah, well done Breadstick! I launched it directly from command line without batch-file...


Featured Post

On Demand Webinar - Networking for the Cloud Era

This webinar discusses:
-Common barriers companies experience when moving to the cloud
-How SD-WAN changes the way we look at networks
-Best practices customers should employ moving forward with cloud migration
-What happens behind the scenes of SteelConnect’s one-click button

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Maven Project: Hibernate Dependencies Conflict 10 87
spring jars download 1 67
ejb on wildfly 5 61
ejb mdb examples 1 38
An old method to applying the Singleton pattern in your Java code is to check if a static instance, defined in the same class that needs to be instantiated once and only once, is null and then create a new instance; otherwise, the pre-existing insta…
Introduction Java can be integrated with native programs using an interface called JNI(Java Native Interface). Native programs are programs which can directly run on the processor. JNI is simply a naming and calling convention so that the JVM (Java…
Viewers will learn about the different types of variables in Java and how to declare them. Decide the type of variable desired: Put the keyword corresponding to the type of variable in front of the variable name: Use the equal sign to assign a v…
Viewers will learn about the regular for loop in Java and how to use it. Definition: Break the for loop down into 3 parts: Syntax when using for loops: Example using a for loop:

734 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question