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When to use TransactionOption.Supported

Posted on 2003-12-08
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Last Modified: 2012-06-27
I have a class that requires to be in a Transaction. I therefore have given it the attribute <Transaction(TransactionOption.Required)>
My class also calls methods in other classes which do work that needs to be in the transaction.
Do I have to add an attribute to those classes as well or will they automatically be in the transaction?

If I don't have to, why would any one ever use the TransactionOption.Supported parameter?

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Question by:mikexxx
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9 Comments
 
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Expert Comment

by:Dranizz
ID: 9897986
Well, if you have many objects in different assemblies that can operate seperatly and together, you can set the transaction object to supported to make them share a transaction if use together.
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by:Dranizz
ID: 9897998
You don't have to add option for other classes, class called in the method with the attribute will be in the transaction, if any fails and exception is thrown, than the transaction fails for all and rollbacked, if no exception is thrown, then trnsaction is commited for all.
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by:Dranizz
ID: 9903727
Is that good enougth?
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Author Comment

by:mikexxx
ID: 9903803
I don't think you are correct. I have just created a transaction and called a method in another DLL. When I throw an exception, everything rolls back. The transaction must be containing what was done in the other DLL.
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Expert Comment

by:Dranizz
ID: 9903839
what option did you use?
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Author Comment

by:mikexxx
ID: 9903861
I created the transaction by having the attribute <Transaction(TransactionOption.Required)>  on the class which inherited ServicedComponent .
The class in the DLL did not inherit ServicedComponent or have any relavent attributes.
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by:Dranizz
ID: 9903868
Yeah, that's what I told you.
"if any fails and exception is thrown, than the transaction fails for all and rollbacked,"

Everything shares the transaction in the method where you specify the transaction option. With supported, if a transaction is already started then it shares it.

With requiredit shares a transac it exist or create one if not.
With requirednew it creates a root transac.

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Author Comment

by:mikexxx
ID: 9903892
Yes but I was calling stuff in another assembly, without the TransactionOption.Supported
 and yet it still was contained within the transaction.

Since this is the case, my question is, why would I ever need to specify TransactionOption.Supported since it is the default.

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Accepted Solution

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Dranizz earned 250 total points
ID: 9904148

In my MCSD book, it says that the configured default value is Required with and IsolationLevel Serializable.
and the unconfigured default value is false.

http://msdn.microsoft.com/library/default.asp?url=/library/en-us/cossdk/htm/pgservices_transactions_9oj7.asp
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