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Query Selection Help

Posted on 2003-12-08
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Last Modified: 2008-03-06
I am trying to display the data in my database but I get the error below:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/anudaysp/public_html/displayServices.php on line 19



Below is my code:

#CONNECT TO MYSQL
$dbcnx = @mysql_connect('localhost',$username,$password) or die("Unable to connect to MySQL");

#CONNECT TO DATABASE
@mysql_select_db($database) or die( "Unable to select database");

#CREATE THE QUERY
$sql = "SELECT S_NAME,SERVICE FROM SERVICE";

#EXECUTE QUERY
$rs = mysql_query($sql,$dbcnx);

#Write the data
while($row = mysql_fetch_array($rs)) <- Line 19
{
      echo("Services: " .$row["s_name"]);
}



Also, What's the best way to debug in PHP?  Believe it or not, today is my second day coding in PHP.
0
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Question by:Isaac
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5 Comments
 
LVL 11

Assisted Solution

by:Zontar
Zontar earned 200 total points
ID: 9901512
Is SELECT S_NAME,SERVICE FROM SERVICE a valid query? Do you have columns named S_NAME and SERVICE in the SERVICE table?

You should respect case-sensitivity for table and column names in MySQL. MySQL on Windows is case-insensitive, but on other operating systems, it's not.

The convention in MySQL is to use lowercase for names of databases, columns, and tables, and uppercase for MySQL keywords. In addition there's a configuraiton option that forces these to be converted to lowercase, even if the table creation statement shows them in uppercase. (However, MySQL keywords are not case-sensitive on any operating system, this is just a convention used to make queries easier to read.)

Use the same case in both PHP and MySQL as well. Your query has S_NAME, but then in the PHP code, you try to write the value $rs["s_name"].

Perhaps you should try

SELECT s_name,service FROM service

or, since you're only writing the value of the S_NAME or s_name column (whichever it is)

SELECT s_name FROM service

Good luck.
0
 
LVL 24

Accepted Solution

by:
shivsa earned 300 total points
ID: 9902739
also change
$rs = mysql_query($sql,$dbcnx);
to
$rs = mysql_query($sql,$dbcnx) or die ("Could not execute query. $sql");

u will know if this part is ok and u are getting $rs ok then u can check whether u are passing correct argument to mysql_fetch_array or not.

0
 
LVL 24

Expert Comment

by:shivsa
ID: 9902750
or for better debugging.

$rs = mysql_query($sql,$dbcnx) or die ("Query '$sql' failed with error message: \"" . mysql_error () . '"');
0
 
LVL 19

Expert Comment

by:Michael701
ID: 9903499
i think your sql is the problem. you MUST qualify the field name when it is the same as the table name.

$sql = "SELECT S_NAME,SERVICE.SERVICE FROM SERVICE";
echo mysql_errno() . ": " . mysql_error(). "\n";

p.s. to resolve this i normally use plural tables

$sql = "SELECT S_NAME,SERVICE FROM SERVICES";

0
 
LVL 11

Expert Comment

by:Zontar
ID: 9903656
>  you MUST qualify the field name when it is the same as the table name.

This is incorrect.

While it's true that it is not a good practice to name a column with the same name as the table it's in, MySQL has no problem with it whatsiever if you choose to do so -- and no special syntax is required to access the column:

CREATE TABLE sometable (
  id INT(8) AUTO_INCREMENT PRIMARY KEY,
  sometable VARCHAR(25)
);

INSERT INTO sometable VALUES (('', 'foo'), ('', 'bar'), ('', 'baz'));

SELECT id,sometable FROM sometable;

id     sometable
---    -----
1      foo
2      bar
3      baz

3 rows in set (0.00 sec)
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