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finding the string before a special character

Posted on 2003-12-10
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Last Modified: 2012-05-05
Suppose i have an xml file.
i have to write an xsl file so that it should allow characters from
a-z and A-Z and numbers and '_' and '/'.
if the string is having any other character then it should display the string before the special character.
if the string is not having any other special characters then it should display normally.

my xml file is:

<?xml version="1.0"?>
<emp>
 <name>srini$sdg</name>
 <name>rama</name>
 <name>rameshs@dg</name>
 <name>r)amki</name>
 <name>ragi</name>
</emp>

in this case the output should be :
srini
rama
rameshs
r
ragi
pease give a solution to this.
thanks
srini.
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Question by:srini_r
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2 Comments
 
LVL 6

Expert Comment

by:metalmickey
ID: 9919513
you could use the substring-before function

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LVL 6

Accepted Solution

by:
PeterCiuffetti earned 25 total points
ID: 9920182
Here's a stylesheet that does what you want.  It uses the translate function to create a variable containing only the special charaters.  it then uses the first of these in the subbstring-before to output the beginning

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="name">
      <!-- translate out the non-special characters, leaving the special characters -->
      <xsl:variable name="specialChars" select="translate(.,'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ_/','')"/>
      <xsl:choose>
            <!-- If there are no special characters, output the whole name -->
            <xsl:when test="string-length($specialChars) = 0">
                  <xsl:value-of select="."/>
            </xsl:when>
            <!-- Otherwise output the string before the first special character -->
            <xsl:otherwise>
                  <xsl:variable name="firstSpecialChar" select="substring($specialChars,1,1)"/>
                  <xsl:value-of select="substring-before(.,$firstSpecialChar)"/>
            </xsl:otherwise>
      </xsl:choose>
</xsl:template>

</xsl:stylesheet>

Pete
0

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