Hi XPUSR,

lo 4 bits of c

c & 0x15

a anyway has 8 bits

a= {lo 4 bits of c}{high 8 bits of a}

((c & 0x15 ) <<8) | a

to get

Cheers!

Sunny:o)

lo 4 bits of c

c & 0x15

a anyway has 8 bits

a= {lo 4 bits of c}{high 8 bits of a}

((c & 0x15 ) <<8) | a

to get

Cheers!

Sunny:o)