Why is my destructor not being called with delete[] ?

#include <iostream>

using namespace std;

class D
{
public:
      D() {}
      ~D() { cout << "D destructor\n"; }
};

int main()
{
      D** array = new D*[5];

      for (int i = 0; i < 5; i++) {
           array[i] = new D();
      }
      //delete array[1];
      delete[] array;

      return 0;
}

Why am I getting no output when I run the code above ?  I get "D destructor" output when I say, e.g. delete array[0].  I thought that this delete[] would call the destructor for each object in turn !

I have stepped into the code with the debugger and

void __cdecl operator delete(void *p) _THROW0()

is being called; but not my destructor.

Why ?

TIA
LVL 19
mrwad99Asked:
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meow00Commented:
Hello try this
-----------
int main()
{
     D** array = new D*[5];

     for (int i = 0; i < 5; i++) {
          array[i] = new D();
     }
     //delete array[1];
    for(int i=0; i<5; i++){
      delete [] array[i] ;}
    delete[] array;

     return 0;
}
----------------------------
 since it is a two dimension array, you have to do it step by step.

 meow ....
0

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mrwad99Author Commented:
>>    for(int i=0; i<5; i++){
      delete [] array[i] ;}
    delete[] array;

second line should be delete array[i].

Yeah cheers for that meow, I was already aware of that, I was just interested as to why the explicit call to delete[] did not work as I thought it would.  Indeed deleting each individual element does result in the destructor being called, as it should.

So I suppose I have answered my own question there.  To delete 2D arrays, the syntax you mentioned should be used.  

GRRRR I AM AN IDIOT ATM AND AM NOT THINKING CORRECTLY.  OF COURSE 2D ARRAYS HAVE TO BE DELETED AS YOU HAVE MENTIONED !

ARGGHHHHHH
0
mrwad99Author Commented:
>> since it is a two dimension array, you have to do it step by step.

Even though I already knew the answer, and indeed answered one of your questions on the same topic, I am going to give you the 20 points, since you have effectively gave me a real hard kick in the butt.  Time for a rest me thinks.

:)
0
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