Hi, if I have a list of words (see below), how can I add them into an array in order and no duplicate?

Hi, if I have a list of words (see below), how can I add them into an array in order and no duplicate?

abc
bbb
djs
opl
abc
knda
bbb
opl
vvv
musclejackAsked:
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prasitleeCommented:
Dear musclejack,
     Try the following code. I am strongly sure that my code would answer your problem.

Option Explicit

Private Sub Command1_Click()

    Dim arrMeng As Variant
    Dim i As Integer
    Dim strMeng As String
   
    arrMeng = Array("abc", "bbb", "djs", "opl", "abc", "knda", "bbb", "opl", "vvv")
   
    QuickSort arrMeng
    strMeng = ""
    For i = 0 To UBound(arrMeng)
        strMeng = strMeng & arrMeng(i) & vbTab
    Next i
   
    MsgBox strMeng

   
   
End Sub
Sub QuickSort(arr As Variant, Optional numEls As Variant, _
    Optional descending As Boolean)

    Dim value As Variant, temp As Variant
    Dim sp As Integer
    Dim leftStk(32) As Long, rightStk(32) As Long
    Dim leftNdx As Long, rightNdx As Long
    Dim i As Long, j As Long
    Dim k As Long
    Dim strPrevious As String
    Dim strCurrent As String
    Dim colTemp As Collection

    ' account for optional arguments
    If IsMissing(numEls) Then numEls = UBound(arr)
    ' init pointers
    leftNdx = LBound(arr)
    rightNdx = numEls
    ' init stack
    sp = 1
    leftStk(sp) = leftNdx
    rightStk(sp) = rightNdx

    Do
        If rightNdx > leftNdx Then
            value = arr(rightNdx)
            i = leftNdx - 1
            j = rightNdx
            ' find the pivot item
            If descending Then
                Do
                    Do: i = i + 1: Loop Until arr(i) <= value
                    Do: j = j - 1: Loop Until j = leftNdx Or arr(j) >= value
                    temp = arr(i)
                    arr(i) = arr(j)
                    arr(j) = temp
                Loop Until j <= i
            Else
                Do
                    Do: i = i + 1: Loop Until arr(i) >= value
                    Do: j = j - 1: Loop Until j = leftNdx Or arr(j) <= value
                    temp = arr(i)
                    arr(i) = arr(j)
                    arr(j) = temp
                Loop Until j <= i
            End If
            ' swap found items
            temp = arr(j)
            arr(j) = arr(i)
            arr(i) = arr(rightNdx)
            arr(rightNdx) = temp
            ' push on the stack the pair of pointers that differ most
            sp = sp + 1
            If (i - leftNdx) > (rightNdx - i) Then
                leftStk(sp) = leftNdx
                rightStk(sp) = i - 1
                leftNdx = i + 1
            Else
                leftStk(sp) = i + 1
                rightStk(sp) = rightNdx
                rightNdx = i - 1
            End If
        Else
            ' pop a new pair of pointers off the stacks
            leftNdx = leftStk(sp)
            rightNdx = rightStk(sp)
            sp = sp - 1
            If sp = 0 Then Exit Do
        End If
    Loop
   
    Set colTemp = New Collection
    strPrevious = ""
    For k = 0 To UBound(arr)
        strCurrent = arr(k)
        If strCurrent = strPrevious Then
        Else
            colTemp.Add strCurrent
        End If
        strPrevious = strCurrent
    Next k
   
    ReDim arr(colTemp.Count)
   
    For k = 1 To colTemp.Count
        strCurrent = colTemp.Item(k)
        arr(k - 1) = strCurrent
    Next k
   
End Sub


0

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musclejackAuthor Commented:
Can you show me the ASP version ?
0
prasitleeCommented:
Dear musclejack,
    I am not sure if I could write this program in ASP or not. Anyway I would try to modify but it take a little bit time to change. I would tell you the progress later. If you would like to get the faster result, you might need to post this question into the Web Programming Session.
                                                     Meng
0
prasitleeCommented:
Dear musclejack,
     Try the following link.
     http://www.planet-source-code.com/vb/scripts/ShowCode.asp?lngWId=4&txtCodeId=6495
     You might need to modify a little bit further.
     Any comment, please let me know.
                                                                       Meng
0
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