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I'M CONFUSED ON HOW TO USE THE IF STATATEMENT

Posted on 2003-12-11
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Last Modified: 2010-04-02
IN THE FOLLOWING PROGRAM
THE USER IS TO ENTER A SINGLE CHAR O FOR OIL G FOR GAS
THE NEXT LINE IS A REAL NUMBER FOR THE COST OF A WELL
NEXT LINE THE USER A CHAR S FOR SULFUR OR CHAR N FOR NO SULFUR
IF S THIS IS FOLLOWED BY THE PERCENT OF SULFUR PRESENT

MY PROBLEM IS THTA I CAN CALC S BUT I CAN SEEM TO CALC N
THE PROBLEM APEARS TO BE IN MY IF STATEMENT BUT I CAN'T SEEM TO FIND IT:
ENCLOSED IS A COPY OF THE CODE AND THE ANSWERS I GET FOR S AND N.

      /////////////////////////////////////////////////////////
//This program file is Gas or Oil
//This program will calculate the amount of gas or oil in a well
//Program Name:  Gas or Oil calculator
//Author: Terence Bell
//Description computes the amount of gas or oil



#include <iostream>
#include <iomanip>
using namespace std;

 double oilCost = 5.50;            //This is the cost of the oil
 double gasCost = 2.20;            //This is the cost of the gas

int main ()
{
      
      char    wellType, sulfurContent;  
    double  costOfWell;
      double  wellVolume, sulfurPresent;
      long int revenue =0;

      double  profit = 0;

      //Member needs to input the type of well
      cout<<"Enter type of well (D=Dry, O=Oil, G=Gas)"<< endl;
      cin >> wellType;

      if ((wellType == 'O') || (wellType == 'G'))
   
{
    cout << "Cost of the well" << endl;
      cin  >> costOfWell;

      cout<< "Enter volume found" << endl;
      cin >> wellVolume;

      cout<< "Enter sulfurContent (N = no sulfur, S = sulfur)"<< endl;
      cin >> sulfurContent;
}
      if (sulfurContent == 'S')
      {
      cout << "Enter Sulfur present in percent" << endl;

      cin >> sulfurPresent;
      }

      if (wellType == 'O')
      //This is the calculation of the oil content
      {  
        revenue = oilCost * (wellVolume - (wellVolume * sulfurPresent));  
            cout<< "The oil revenue is $ " << revenue <<endl;
      }
      
      if (wellType == 'G')//This is the calculation of the gas content
      {
            
            revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
            cout<< "The gas revenue is $ " << revenue <<endl;
      }

       else
       {
            revenue = gasCost * wellVolume;
            cout<< "The gas revenue is $ " << revenue <<endl;             
      
     
       }

        profit = revenue - costOfWell;
      
        cout<< "Profit is $ "  << profit << endl;
     
        {
   
         if (profit >= 50000)
      {
       
            cout << "It's a Gusher: " << profit << endl;
        }
       

      return 0;
}
}
0
Comment
Question by:tbell000
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7 Comments
 
LVL 9

Expert Comment

by:tinchos
ID: 9925512
Hi tbell000,

I'll give you just 2 suggestions

1) indent your code, so that it will be clear what you're doing, and when (if the condition is true or not)
2) I've found a couple of {} that were misplaced, try with this one


/////////////////////////////////////////////////////////
//This program file is Gas or Oil
//This program will calculate the amount of gas or oil in a well
//Program Name:  Gas or Oil calculator
//Author: Terence Bell
//Description computes the amount of gas or oil



#include <iostream>
#include <iomanip>
using namespace std;

double oilCost = 5.50;          //This is the cost of the oil
double gasCost = 2.20;          //This is the cost of the gas

int main ()
{

      char    wellType, sulfurContent;  
      double  costOfWell;
      double  wellVolume, sulfurPresent;
      long int revenue =0;

      double  profit = 0;

      //Member needs to input the type of well
      cout<<"Enter type of well (D=Dry, O=Oil, G=Gas)"<< endl;
      cin >> wellType;

      if( (wellType == 'O') || (wellType == 'G') )
      {
            cout << "Cost of the well" << endl;
            cin  >> costOfWell;

            cout<< "Enter volume found" << endl;
            cin >> wellVolume;

            cout<< "Enter sulfurContent (N = no sulfur, S = sulfur)"<< endl;
            cin >> sulfurContent;
      }
      if( sulfurContent == 'S' )
      {
            cout << "Enter Sulfur present in percent" << endl;

            cin >> sulfurPresent;
      }

      if( wellType == 'O' ) //This is the calculation of the oil content
      {  
            revenue = oilCost * (wellVolume - (wellVolume * sulfurPresent));  
            cout<< "The oil revenue is $ " << revenue <<endl;
      }

      if( wellType == 'G' ) //This is the calculation of the gas content
      {
            revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
            cout<< "The gas revenue is $ " << revenue <<endl;
      }

      else
      {
            revenue = gasCost * wellVolume;
            cout<< "The gas revenue is $ " << revenue <<endl;          
      }

      profit = revenue - costOfWell;

      cout<< "Profit is $ "  << profit << endl;


      if (profit >= 50000)
      {
            cout << "It's a Gusher: " << profit << endl;
      }

      return 0;
}

Cheers!
0
 
LVL 24

Expert Comment

by:shivsa
ID: 9925579
u have misplaced { }, try to place them properly. and see if it works.
0
 

Author Comment

by:tbell000
ID: 9925757
STILL WILL NOT SOVLE FOR N THE PROBLEM SEEMS TO BE HERE

  if( wellType == 'G' ) //This is the calculation of the gas content
     {
          revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
          cout<< "The gas revenue is $ " << revenue <<endl;
     }

     else
     {
          revenue = gasCost * wellVolume;
          cout<< "The gas revenue is $ " << revenue <<endl;        
0
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LVL 30

Expert Comment

by:Mayank S
ID: 9926128
>> I'll give you just 2 suggestions

:-) I'll give you one more. All of us can read, so STOP WRITING IN CAPS ALL THE TIME :-)

By the way, what error is it goving now?

Cheers,
Mayank.
0
 
LVL 30

Expert Comment

by:Mayank S
ID: 9926137
>> goving now

giving now
0
 
LVL 24

Accepted Solution

by:
shivsa earned 500 total points
ID: 9926194
Just add this else statement after u check about sulfer content.
-----------------------
 if( sulfurContent == 'S' )
     {
          cout << "Enter Sulfur present in percent" << endl;
          cin >> sulfurPresent;
     }
else {
           sulfurPresent = 0;
    }
0
 
LVL 30

Expert Comment

by:Mayank S
ID: 9926374
Oh right.... its not Java :-) the value won't be initialized by itself to 0.
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