Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

I'M CONFUSED ON HOW TO USE THE IF STATATEMENT

Posted on 2003-12-11
7
Medium Priority
?
236 Views
Last Modified: 2010-04-02
IN THE FOLLOWING PROGRAM
THE USER IS TO ENTER A SINGLE CHAR O FOR OIL G FOR GAS
THE NEXT LINE IS A REAL NUMBER FOR THE COST OF A WELL
NEXT LINE THE USER A CHAR S FOR SULFUR OR CHAR N FOR NO SULFUR
IF S THIS IS FOLLOWED BY THE PERCENT OF SULFUR PRESENT

MY PROBLEM IS THTA I CAN CALC S BUT I CAN SEEM TO CALC N
THE PROBLEM APEARS TO BE IN MY IF STATEMENT BUT I CAN'T SEEM TO FIND IT:
ENCLOSED IS A COPY OF THE CODE AND THE ANSWERS I GET FOR S AND N.

      /////////////////////////////////////////////////////////
//This program file is Gas or Oil
//This program will calculate the amount of gas or oil in a well
//Program Name:  Gas or Oil calculator
//Author: Terence Bell
//Description computes the amount of gas or oil



#include <iostream>
#include <iomanip>
using namespace std;

 double oilCost = 5.50;            //This is the cost of the oil
 double gasCost = 2.20;            //This is the cost of the gas

int main ()
{
      
      char    wellType, sulfurContent;  
    double  costOfWell;
      double  wellVolume, sulfurPresent;
      long int revenue =0;

      double  profit = 0;

      //Member needs to input the type of well
      cout<<"Enter type of well (D=Dry, O=Oil, G=Gas)"<< endl;
      cin >> wellType;

      if ((wellType == 'O') || (wellType == 'G'))
   
{
    cout << "Cost of the well" << endl;
      cin  >> costOfWell;

      cout<< "Enter volume found" << endl;
      cin >> wellVolume;

      cout<< "Enter sulfurContent (N = no sulfur, S = sulfur)"<< endl;
      cin >> sulfurContent;
}
      if (sulfurContent == 'S')
      {
      cout << "Enter Sulfur present in percent" << endl;

      cin >> sulfurPresent;
      }

      if (wellType == 'O')
      //This is the calculation of the oil content
      {  
        revenue = oilCost * (wellVolume - (wellVolume * sulfurPresent));  
            cout<< "The oil revenue is $ " << revenue <<endl;
      }
      
      if (wellType == 'G')//This is the calculation of the gas content
      {
            
            revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
            cout<< "The gas revenue is $ " << revenue <<endl;
      }

       else
       {
            revenue = gasCost * wellVolume;
            cout<< "The gas revenue is $ " << revenue <<endl;             
      
     
       }

        profit = revenue - costOfWell;
      
        cout<< "Profit is $ "  << profit << endl;
     
        {
   
         if (profit >= 50000)
      {
       
            cout << "It's a Gusher: " << profit << endl;
        }
       

      return 0;
}
}
0
Comment
Question by:tbell000
7 Comments
 
LVL 9

Expert Comment

by:tinchos
ID: 9925512
Hi tbell000,

I'll give you just 2 suggestions

1) indent your code, so that it will be clear what you're doing, and when (if the condition is true or not)
2) I've found a couple of {} that were misplaced, try with this one


/////////////////////////////////////////////////////////
//This program file is Gas or Oil
//This program will calculate the amount of gas or oil in a well
//Program Name:  Gas or Oil calculator
//Author: Terence Bell
//Description computes the amount of gas or oil



#include <iostream>
#include <iomanip>
using namespace std;

double oilCost = 5.50;          //This is the cost of the oil
double gasCost = 2.20;          //This is the cost of the gas

int main ()
{

      char    wellType, sulfurContent;  
      double  costOfWell;
      double  wellVolume, sulfurPresent;
      long int revenue =0;

      double  profit = 0;

      //Member needs to input the type of well
      cout<<"Enter type of well (D=Dry, O=Oil, G=Gas)"<< endl;
      cin >> wellType;

      if( (wellType == 'O') || (wellType == 'G') )
      {
            cout << "Cost of the well" << endl;
            cin  >> costOfWell;

            cout<< "Enter volume found" << endl;
            cin >> wellVolume;

            cout<< "Enter sulfurContent (N = no sulfur, S = sulfur)"<< endl;
            cin >> sulfurContent;
      }
      if( sulfurContent == 'S' )
      {
            cout << "Enter Sulfur present in percent" << endl;

            cin >> sulfurPresent;
      }

      if( wellType == 'O' ) //This is the calculation of the oil content
      {  
            revenue = oilCost * (wellVolume - (wellVolume * sulfurPresent));  
            cout<< "The oil revenue is $ " << revenue <<endl;
      }

      if( wellType == 'G' ) //This is the calculation of the gas content
      {
            revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
            cout<< "The gas revenue is $ " << revenue <<endl;
      }

      else
      {
            revenue = gasCost * wellVolume;
            cout<< "The gas revenue is $ " << revenue <<endl;          
      }

      profit = revenue - costOfWell;

      cout<< "Profit is $ "  << profit << endl;


      if (profit >= 50000)
      {
            cout << "It's a Gusher: " << profit << endl;
      }

      return 0;
}

Cheers!
0
 
LVL 24

Expert Comment

by:shivsa
ID: 9925579
u have misplaced { }, try to place them properly. and see if it works.
0
 

Author Comment

by:tbell000
ID: 9925757
STILL WILL NOT SOVLE FOR N THE PROBLEM SEEMS TO BE HERE

  if( wellType == 'G' ) //This is the calculation of the gas content
     {
          revenue = gasCost * (wellVolume - (wellVolume * sulfurPresent));
          cout<< "The gas revenue is $ " << revenue <<endl;
     }

     else
     {
          revenue = gasCost * wellVolume;
          cout<< "The gas revenue is $ " << revenue <<endl;        
0
Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

 
LVL 30

Expert Comment

by:Mayank S
ID: 9926128
>> I'll give you just 2 suggestions

:-) I'll give you one more. All of us can read, so STOP WRITING IN CAPS ALL THE TIME :-)

By the way, what error is it goving now?

Cheers,
Mayank.
0
 
LVL 30

Expert Comment

by:Mayank S
ID: 9926137
>> goving now

giving now
0
 
LVL 24

Accepted Solution

by:
shivsa earned 2000 total points
ID: 9926194
Just add this else statement after u check about sulfer content.
-----------------------
 if( sulfurContent == 'S' )
     {
          cout << "Enter Sulfur present in percent" << endl;
          cin >> sulfurPresent;
     }
else {
           sulfurPresent = 0;
    }
0
 
LVL 30

Expert Comment

by:Mayank S
ID: 9926374
Oh right.... its not Java :-) the value won't be initialized by itself to 0.
0

Featured Post

Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Templates For Beginners Or How To Encourage The Compiler To Work For You Introduction This tutorial is targeted at the reader who is, perhaps, familiar with the basics of C++ but would prefer a little slower introduction to the more ad…
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
The goal of the tutorial is to teach the user how to use functions in C++. The video will cover how to define functions, how to call functions and how to create functions prototypes. Microsoft Visual C++ 2010 Express will be used as a text editor an…
The viewer will learn how to use the return statement in functions in C++. The video will also teach the user how to pass data to a function and have the function return data back for further processing.

876 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question