Solved

Recurrence relation with Square roots in each term..

Posted on 2004-03-22
9
589 Views
Last Modified: 2011-08-18
Hi experts,
    How to solve a recurrence relation that have Square roots in each term...

    I can solve the normal recurrence relation problem (that hav no square roots)

    Give me some idea...

    Q will be like this

   ROOT(Rn) = ROOT(Rn-1)+ 2.ROOT(Rn-2)  with initial condition R0=R1=1

Rosh :)
0
Comment
Question by:Roshan Davis
  • 5
  • 4
9 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 10655843
Rn = Sn²
where
Sn = (Sn-1) + 2×(Sn-2)
0
 
LVL 23

Author Comment

by:Roshan Davis
ID: 10655884
Thankx for ur comment :)

Calculated associated equation
square(X) = X + 2
and itz roots are (x-2)(x+1)

C1 = u(-1)+v(2)
C2 = u.square(-1)+ v. square(2)

And reached the result

Cn = (-1/3)(-1)^n + (1/3)(2)^n

this is the Recurrence relation for "Sn = (Sn-1) + 2×(Sn-2)"

Is this correct?

Rosh :)
0
 
LVL 84

Expert Comment

by:ozo
ID: 10655919
or in closed form
Rn = (((-1)^n+2^(n+1))/3)^2
0
 
LVL 84

Expert Comment

by:ozo
ID: 10655927
Sorry, didn't see you had solved it
0
Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

 
LVL 23

Author Comment

by:Roshan Davis
ID: 10655941
But answers were different...?
Can u show me some steps...
0
 
LVL 23

Author Comment

by:Roshan Davis
ID: 10655984
Hi, you can see the question here http://www.coolgoose.com/sites/puttalu/
0
 
LVL 84

Expert Comment

by:ozo
ID: 10656001
They were different because you used C1=C2=1, while I used R0=R1=1
0
 
LVL 23

Author Comment

by:Roshan Davis
ID: 10656009
So, for this Q http://www.coolgoose.com/sites/puttalu/ which is correct ?
Rosh :)
0
 
LVL 84

Accepted Solution

by:
ozo earned 125 total points
ID: 10656073
for r0=r1=1
Rn = (((-1)^n+2*2^n)/3)^2
is correct
((-1)^0 + 2*2^0)/3 = 1
((-1)^1 + 2*2^1)/3 = 1
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Cumulative Distribution 2 34
Relative frequency assesment method 2 48
Math Stumper 6 48
deducing meaning of a word from its prefix-question 7 70
This article seeks to propel the full implementation of geothermal power plants in Mexico as a renewable energy source.
This article provides a brief introduction to tissue engineering, the process by which organs can be grown artificially. It covers the problems with organ transplants, the tissue engineering process, and the current successes and problems of the tec…
Internet Business Fax to Email Made Easy - With  eFax Corporate (http://www.enterprise.efax.com), you'll receive a dedicated online fax number, which is used the same way as a typical analog fax number. You'll receive secure faxes in your email, f…
This is a video describing the growing solar energy use in Utah. This is a topic that greatly interests me and so I decided to produce a video about it.

920 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

16 Experts available now in Live!

Get 1:1 Help Now