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Posted on 2004-03-23
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I have a linear equation I am having trouble solving:

x/5 + 2y = 8/5
3x/5 + y/2 = -7/10
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5(1/5x+2y = 8/5)
x + 10y = 8
x = -10y + 8

10(3x/5 + y/2 = -7/10)
2(3x) + 5y = -7

2[3(-10y + 8)] + 5y = -7
2[-30y + 24] + 5y = -7
-60y + 48 + 5y = -7
-55y + 48 = -7
-55y = -55
y = 1

x = -10(y) + 8
x = -10 + 8
x = -2


is the solution set (-2,1) ?
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Question by:BrianGEFF719
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