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How To Post From A Script

Posted on 2004-03-23
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Last Modified: 2010-07-27
I need to post some XML to an external web address (Java servlet on another web server) from within a shopping cart written in aspl. I need example code for how to do this. I also need to know if it can be done to an SSL address.
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Question by:jimkat
3 Comments
 
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by:ap_sajith
ID: 10665171
Have you looked into XMLHTTP as an option?. You can use XMLHTTP to send an XML stream to the other server and recieve the output from the other server.

eg:

Dim xmlhttp
Set xmlhttp = CreateObject("Microsoft.XMLHTTP")
'Open a connection and send a request to the server in the form of an XML fragment
xmlhttp.Open("POST", "http://www.yourserver.com/yourpage.asp", False)
xmlhttp.send("<reqtimesheet user='jimbob'/>")
Response.WRite Cmlhttp.ResponseText ' ** Use ResponseXML if an XML stream is returned **

Check out these articles for further info..

http://www.15seconds.com/issue/991125.htm
http://www.eggheadcafe.com/articles/20010209.asp

Cheers!!
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Accepted Solution

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sybe earned 500 total points
ID: 10665642
Function PostToUrl(url,data)
    Dim oXMLHttpRequest
    Set oXMLHttpRequest = Server.CreateObject("Microsoft.XMLHTTP")
    oXMLHttpRequest.Open "POST", url, False
    oXMLHttpRequest.setRequestHeader "Content-Type", "application/x-www-form-urlencoded"
    oXMLHttpRequest.Send data
    PostToUrl = oXMLHttpRequest.responseText
    Set oXMLHttpRequest = Nothing
End Function
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Expert Comment

by:fozylet
ID: 10665725
If it is SOAP...

function GetSendSoapResponse(strMessage,strURL,strAction)
      ' must create an XML document to format the request message
      Dim xmlhttp, strSoap
      Set xmlhttp = Server.CreateObject("Msxml2.ServerXMLHTTP")

      ' Build the XML/SOAP request message
      strSoap = strMessage
      ' Send the request to the server
      xmlhttp.Open "POST", strURL, False
      xmlhttp.setRequestHeader "Man", "POST " & strURL & " HTTP/1.1"
      xmlhttp.setRequestHeader "Content-Type", "text/xml; charset=utf-8"
      xmlhttp.setRequestHeader "SOAPAction", strAction

      'send the request to the webservice
      xmlhttp.send(strSoap)

      If xmlhttp.Status = 200 Then 'if response code is OK
      GetSendSoapResponse = xmlhttp.responseText
      Else 'an error has occurred
      GetSendSoapResponse = ""
      Response.Write("Web service Server Error...<br>")
      Response.Write("status = " & xmlhttp.status)
      Response.Write("<br>" & xmlhttp.statusText)
      Response.Write("<br><pre>" & Request.ServerVariables("ALL_HTTP") & "</pre>")
      End If
      Set xmlhttp = nothing
end function
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