Solved

Double number Rounding issue

Posted on 2004-03-24
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Last Modified: 2010-04-01
Hi Experts,

Look at the simple example

double a = 1440.0;
double b = 0.06;
double c = a * b;

out.println("Result " + c)  gives 86.39999999999999;

Where
out.println("Result " + 1440.0 * 0.06) gives exact value 86.4   which is correct;

Does anybody knows why this happens, and how to fix a*b -> 86.4


Thanks
Britto
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Question by:de_britto
  • 2
6 Comments
 
LVL 27

Accepted Solution

by:
rrz earned 25 total points
ID: 10672181
>out.println("Result " + 1440.0 * 0.06) gives exact value 86.4   which is correct;
I don't get that result on my Tomcat 5 and  JDK1.4 .  I get   86.39999999999999  

>how to fix a*b -> 86.4
Here is one way.  

<%
float a = 1440.0f;
float b = 0.06f;
float c = a * b;
out.println("Float Result = " + c);  
%>
0
 
LVL 92

Assisted Solution

by:objects
objects earned 25 total points
ID: 10674232
Use DecimalFormat class to display to the number of required decuimal places.


DecimalFormat df = new DecimalFormat("#.##");
out.println("Result "+df.format(c));  
0
 
LVL 9

Expert Comment

by:mmuruganandam
ID: 10674601
DecimalFormat format = new DecimalFormat("#.#");
out.println(format.format(c));            
0
 
LVL 27

Expert Comment

by:rrz
ID: 10678566
to objects and mmuruganandam,  
Great, your solutions work for the given values, because DecimalFormat uses half-even rounding  for formatting.  

 "de britto" wanted the  exact value
>gives exact value 86.4   which is correct  

But what if the variables change ?  (  b = 0.061111 for example )  
How could your solution be applied to the general case ?  

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