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Interbase 5.5 Left Join (easy question lots of points)

matchbx27
matchbx27 asked
on
Medium Priority
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Last Modified: 2013-12-09
Ok I know this is a simple question, but after searching 4 or 5 interbase pdf files and google....

Can anyone please tell me how to do a LEFT JOIN in Interbase 5.5?


I am also using the old style SQL joins

select p.parentName, c.ChildName from Parent p, Child c where p.parent = c.parent;


I need to know the syntax to be used in the where clause?

I assigned so many point because I would like an answer within the next 30 minutes or so.

Thanks,
matchbx
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idt

Commented:
Select L.fieldOne, R.FieldOne from
LeftTable L left outer join RightTable R
on (L.fieldname=R.fieldname)
where L.field=someval
order by ...

Actually there is no left join, its a left outer join.  All the rows from the left table and column from the right where the hoin criteria matches.

Daniel P.

Author

Commented:
I don't mean to be so hard IDT, however, you did not read my post.

I am using the old style join...
I gave a simplistic example...

my join is in the where clause...

WHERE p.Parent = c.Parent

I have tried the following that works on other databases

p.parent *= c.Parent
p.parent (+) = c.parent
p.parent *>= c.parent

What works with interbase 5.5.
idt

Commented:
There is no left outer join in SQL89 syntax, some databases supported it through wacky join syntax, like oracle had a += or something like that.
So I beleive that you must use SQL92 syntax.


Further, you can put additional predicates in the on clause:
on (L.fieldname=R.fieldname and R.fieldX<>1 and ...)
or put the additonal predicates in the where clause.

Do check the query plan, to ensure that additional predicate placements do not cause the query to exclude indices where they should be used.

Daniel P.
idt

Commented:
Why must you use the SQL89 syntax?
I may be able to help you come up with another solution

Author

Commented:
Since I am new to Interbase 5.5 (this is a project for another department), I was under the assumption that Interbase 5.5 only supported SQL 89.  It seems as though I can use SQL 92.


Here's my problem:  I have to do a 7 table join.  6 of the table is 1 to 1. 1 table is a one to many.  In case you didn't notice, I'm doing this to create a view.

SQL 89 Version
Create View nvTotalPartsProduced1 (ProdLogID, ProdDate, ProdShift, JobNumber, PartNumber, TotalPartsProduced, ScrapCode, ScrapQty) as


SELECT
      PLH.PRODLOG_ID,
      PLH.PRODDATE,
      PSH.PRODSHIFT,
      JH.JOB_NUMBER,
      PI.PART_NUMBER,
      PPH.QUANTITY,
      PSCH.QUANTITY,
      SI.NAME
FROM
      PARTINFO PI,
      PRODLOGHIST PLH,
      PRODSHIFTHIST PSH,
      JOBHIST JH,
      PRODPARTHIST PPH,
      PRODSCRAPHIST PSCH,
      SCRAPINFO SI
WHERE
      PLH.PRODSHIFT_ID = PSH.PRODSHIFT_ID AND
      PLH.PRODLOG_ID = PPH.PRODLOG_ID AND
      PLH.JOB_ID = JH.JOB_ID AND
      PI.PART_ID = PPH.PART_ID AND
      PLH.PRODLOG_ID = PSCH.PRODLOG_ID AND        (This is where I need a left outer join)
      PSCH.SCRAP_ID = SI.SCRAP_ID;


SLQ 92 Version

Create View nvTotalPartsProduced1 (ProdLogID, ProdDate, ProdShift, JobNumber, PartNumber, TotalPartsProduced, ScrapCode, ScrapQty) as


SELECT
      PLH.PRODLOG_ID,
      PLH.PRODDATE,
      PSH.PRODSHIFT,
      JH.JOB_NUMBER,
      PI.PART_NUMBER,
      PPH.QUANTITY,
      PSCH.QUANTITY,
      SI.NAME
FROM
      ((((((PRODLOGHIST PLH JOIN PRODSHIFTHIST PSH ON PLH.PRODSHIFT_ID = PSH.PRODSHIFT_ID)
      JOIN JOBHIST JH ON PLH.JOB_ID = JH.JOB_ID)
      JOIN PRODPARTHIST PPH ON PLH.PRODLOG_ID = PPH.PRODLOG_ID)
      JOIN PARTINFO PI ON PI.PART_ID = PPH.PART_ID)
      LEFT OUTER JOIN PRODSCRAPHIST PSCH ON PLH.PRODLOG_ID = PSCH.PRODLOG_ID)  
      JOIN SCRAPINFO SI ON PSCH.SCRAP_ID = SI.SCRAP_ID);


The left outer join in the SQL 92 Version appears to work the same as a normal join.
idt

Commented:
Your syntax appears correct, except it looks like you have the last two columns reversed.

When you say that it works the same as a normal (inner) join, do you mean you are stiff having problems and the query has the wrong result set,

or are you commenting that the syntax is the same for join and left outer join ?

Author

Commented:
the result set that is returned is the same.

Author

Commented:
Thanks for the info on the last two columns.
idt

Commented:
Need clarification:

1 )for PRODSCRAPHIST.PRODLOG_ID, is there;
   A. always AT LEAST one row matching  PRODLOGHIST.PRODLOG_ID;
   B. sometimes one row  matching  PRODLOGHIST.PRODLOG_ID;
   C. always one row matching  PRODLOGHIST.PRODLOG_ID;

2) Do you get different behavior executing the query / selecting from the view


Although even without further clarification,

When I look at your tables, SCRAPINFO should be a left outer join aswell.

Commented:
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Author

Commented:
1 )for PRODSCRAPHIST.PRODLOG_ID, is there;
   C. always one row matching  PRODLOGHIST.PRODLOG_ID;


However looking at it a little differently

for PRODLOGHIST.PRODLOG_ID there is
      0, 1 or many rows matching PRODSCRAPHIST.PRODLOG_ID


Thanks for claifying how SCRAPINFO should be joined.  That may be my problem.  I'm going to try that now.

Author

Commented:
Changing the last join to a left join did the trick...  new query is as follows:


Create View nvTotalPartsProduced1 (ProdLogID, ProdDate, ProdShift, JobNumber, PartNumber, TotalPartsProduced, ScrapCode, ScrapQty) as


SELECT
     PLH.PRODLOG_ID,
     PLH.PRODDATE,
     PSH.PRODSHIFT,
     JH.JOB_NUMBER,
     PI.PART_NUMBER,
     PPH.QUANTITY,
     PSCH.QUANTITY,
     SI.NAME
FROM
     ((((((PRODLOGHIST PLH JOIN PRODSHIFTHIST PSH ON PLH.PRODSHIFT_ID = PSH.PRODSHIFT_ID)
     JOIN JOBHIST JH ON PLH.JOB_ID = JH.JOB_ID)
     JOIN PRODPARTHIST PPH ON PLH.PRODLOG_ID = PPH.PRODLOG_ID)
     JOIN PARTINFO PI ON PI.PART_ID = PPH.PART_ID)
     LEFT OUTER JOIN PRODSCRAPHIST PSCH ON PLH.PRODLOG_ID = PSCH.PRODLOG_ID)  
     LEFT JOIN SCRAPINFO SI ON PSCH.SCRAP_ID = SI.SCRAP_ID);


Thanks for the help idt

matchbx
idt

Commented:
Glad it all worked out.  Sorry we didn't meet your 30 minute window.. next time :)

Author

Commented:
That's ok... I knew I was dreaming anyway.
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