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# How to Integer to a string

Posted on 2004-03-25
Medium Priority
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I Sorry for this quiestion but i dont have idea of how to do this
how can i convert a string to a integer
Felipe
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Question by:Felipe1976
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Expert Comment

ID: 10684062
int x = Integer.parseInt("12345");
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Accepted Solution

dentrita earned 400 total points
ID: 10684085
toString
public String toString()
Returns a String object representing this Integer's value. The value is converted to signed decimal representation and returned as a string, exactly as if the integer value were given as an argument to the toString(int) method.

Overrides:
toString in class Object
Returns:
a string representation of the value of this object in base 10.

or can try

Integer.parseInt(x) converts String to int.
0

LVL 92

Expert Comment

ID: 10684101
int i = 20;
String s = Integer.toString(i);
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LVL 30

Expert Comment

ID: 10684349
objects....

>> convert a string to a integer

String s = Integer.toString(i)  ??? Perhaps typed that a little too fast ;-) ?

Anyway, you can also use: int i = new Integer ( stringObject ).intValue (). However, it might be better to use Integer.parseInt ( stringObject ) as it is useless to instantiate an extra object.
0

Expert Comment

ID: 10684514
U can use the following example...

String str = "10";
int strValue = Integer.parseInt(str).intValue();

which would give the value 10 into the variable strValue.

Regards,
0

LVL 92

Expert Comment

ID: 10684556
> String s = Integer.toString(i)  ??? Perhaps typed that a little too fast ;-) ?

Not really.
Perhaps Felipe1976 typed the question too fast :)

Q. "How to Integer to a string"
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Expert Comment

ID: 10684584
Is the question for Converting a string to an integer or the other way???

Regards,
0

Expert Comment

ID: 10684603
String str1 = "101";
int intVal = Integer.parseInt(str1);

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LVL 30

Expert Comment

ID: 10684632
>> int strValue = Integer.parseInt(str).intValue();

No. Integer.parseInt () is enough. You cannot do an intValue () over a result from parseInt () because parseInt () returns a simple 'int and not an Integer object. Or else you can do: new Integer ( str ).intValue () -> but like I said, its a useless instantiation of an extra object.
0

Expert Comment

ID: 10684647
Ok
0

LVL 30

Expert Comment

ID: 10713681
Felipe1976,

We still don't know if you were trying to convert a String to an integer or an integer to a String?
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