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Sockets

Posted on 2004-03-26
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Last Modified: 2008-02-01
why does socket.getLocalAddress() put a slash in front of the adress
ex. /192.168.1.100
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Question by:tricks801
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19 Comments
 
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objects earned 500 total points
ID: 10691523
cause thats the format toString() uses.

If u don't want it try:

getLocalAddress().getHostName();
or
getLocalAddress().getHostAddress();
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by:GrandSchtroumpf
ID: 10691526
because there is no defined protocol.
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by:GrandSchtroumpf
ID: 10691536
with a defined protcol such as ftp or http, you would get
ftp:/192.168.1.100 or http:/192.168.1.100
so without the protocol, you still keep the "/".
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LVL 92

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by:objects
ID: 10691547
> because there is no defined protocol.

An IP address doesn't have a protocol does it?
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by:objects
ID: 10691563
The slash is actual used to seperate hostname and address. But in your case the name is unknown so it is blank.
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by:GrandSchtroumpf
ID: 10691577
note that when you define a protocol and a port,
you use something like this http:/192.168.1.100:80
you can see that the separator is ":"
so, again, if you dont specify neither the protocol nor the port, you just get "/192.168.1.100"
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by:GrandSchtroumpf
ID: 10691597
> An IP address doesn't have a protocol does it?
i agree, but we're not talking about an ip address here, we're talking about an instance of SocketAddress...  and its toString() method as you mentioned before
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by:objects
ID: 10691600
> note that when you define a protocol and a port,

An IP address does not have a protocol or a port.

> you use something like this http:/192.168.1.100:80

That is not an IP address, 192.168.1.100 is the IP address

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by:GrandSchtroumpf
ID: 10691608
i was just explaining why the toString method leaves the slash.
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by:objects
ID: 10691615
> but we're not talking about an ip address here

I think we actually are

> we're talking about an instance of SocketAddress

Even if we were the same applies.
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by:GrandSchtroumpf
ID: 10691655
oops, it's not an instance of SocketAddress but an instance of java.net.InetAddress.
SocketAddress is for ServeSocket.
javadoc says about InetAddress:
"This class represents an Internet Protocol (IP) address."
which talks about "Protocol" as well as "(IP) address".
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by:objects
ID: 10691696
Yes the *Internet* Protocol :) Thats what IP stands for.
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by:GrandSchtroumpf
ID: 10691716
> The slash is actual used to seperate hostname and address. But in your case the name is unknown so it is blank.
ok, that's fine with me.
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by:GrandSchtroumpf
ID: 10691727
i was reading the wrong javadoc page.  :-)
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by:Tommy Braas
ID: 10691750
There are several layers of protocols. The Internet Protocol (as in IP) sits on the lower levels of the protocol stack and handles routing of packets. The TCP part of TCP/IP handles packet ordering, and connections for connection based communication.

An IPv4 address is x.y.z.w, where each x,y,z and w can hold values same as an unsigned byte. A port, however is local "routing" information, dependent on a protocol sitting on top of TCP/IP. You need both to make a connection to another computer over TCP/IP.

http, which is another protocol, but an application layer protocol, sits on top of TCP/IP, but is separate from TCP/IP.
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by:GrandSchtroumpf
ID: 10691813
> http, which is another protocol, but an application layer protocol, sits on top of TCP/IP, but is separate from TCP/IP.
i agree, http has nothing to do with this question.
sorry for all this mess i created.
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by:Tommy Braas
ID: 10691879
No worries mate  ;-)
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by:objects
ID: 10691888
> sorry for all this mess i created.

sok :)
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by:objects
ID: 10749684
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