keeping the value of an int

Then you must have 'sent' as an instance variable of the class. It should be private

im not sure what you mean.

ive change it from
public int sent;

to
private int sent;

but same problem

Sorry, i slightly misread your question. On the face of it, there shouldn't be a problem

private int sent;

public int getSent() {
      return sent;
}

public void go() {
      // somthing or other
      sent++;
}

..........

yourClass.go();
int sent = yourClass.getSent();
yourClass.go();
int sent = yourClass.getSent();

//etc.

I dont think you know what i mean. Each time i run the go() method the value of the int "sent" determines what happens within the method( due to if statements). The first time i run the method, its ok, because int is set to 0; by the end of the method however int is set to 1. The next time i run the method, it should give me a different result, because int is now 1. But it doesnt, each time i press the button, the method is called and the int is set back to 0;

To assist with what CEHJ is saying, your variable is back to zero because it is declared as a local variable (it is in scope only inside that method) so when the method returns the memory for 'sent' is released.
 (re-calling the method declares a new integer).

   You need to make it as CEHJ shows above, where it is declared as an instance variable and so remains scope for the whole instance. ie. when you return from the method, as long as the object still exists in memory then you will have access to it.

The interesting thing is twobitadder has echoed my first comment. The reason i changed my mind is that in this example you posted:

>>
public class go
{
public int sent;

public go()
{



}
>>

the variable sent IS an instance variable. However, i suspect that either:

a. the code is not actually as  you posted, or
b. there is another, local, variable named 'sent' that's covering up the instance variable

the code is as i posted.

the code is as i posted.

Please post the actual code

>> the method go() is what im calling

So,
1) your class is called go?  (btw, in java classes better start with an upper case, Go)

2) you are calling the method go()
   
    Do you mean you call the constructor? How?
    By performing a

           new go()       ?

   Then it's normal that your variable sent is set back to zero.
   In fact it isn't. You just created a new instance of the class and so the "sent" variable is initialized at 0.

Could that be possible?

I miss-parsed the method, since there is a class called go and a constructor called go, with no real method.

To clear up my echo of your SECOND comment, I was attempting to clarify the reason for using an instance variable rather than a local variable.

znnyx your too cocky for your own good. Ive just solved the problem thanks to rukumam. All i had to do was set the variable to static as below.

private static int sent;

Thanks CEHJ and rukumam.

i made a mistake when entering the code originally. It looked more like this.

public class go
{
public int sent;

public go()
{
//no code in here at all
}
public String reply(Vector enter )
{
//a lot of if statements where the int is changed. This is the method i kept recalling and everytime i did "sent" was back to 0.
}
}

LOL - whatever you'd like to say about zzynx, he's actually guessed precisely what was happening. I'm not sure why you'd repeatedly call the constructor and trap the value in a static variable, but it sounds like a mighty bad idea...

>> whatever you'd like to say about zzynx, he's actually guessed precisely what was happening.
Thanks CEHJ.  That's exactly what I did.
Sometimes we get bad info (or not even half the info) and nevertheless we try to help.

And poiu77, before you start flaming, just think that we are trying to help you.
But OK, if you think I'm cocky I'll note that.
There are enough others that can help you out.
I'll won't spoil my precious time in trying to decode your (even wrong) info and answering it.