Solved

Sibling Reference

Posted on 2004-04-01
13
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Last Modified: 2008-03-06
Hi:
    The following code indicates that I cannot assign an object to a sibling reference. Why??

class Parent
{

}

class DerivedOne extends Parent
{
}

class DerivedTwo extends Parent
{
}

class Test
{  public static void main (String args[])
   {  Parent p = new Parent();
     
      DerivedOne d1 = new DerivedOne();
     
      DerivedTwo d2 = new DerivedTwo();
     
      d1 =(DerivedOne) d2;
   
   }
   
   
}  


0
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Question by:LearningJava
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13 Comments
 
LVL 20

Accepted Solution

by:
Venabili earned 350 total points
ID: 10732044
It is normal.

DerivedOne and DerivedTwo are extending Parent but they both are different classes with their own methods.

You can cast a Parent object to any of these two... but you can't cast them to each other. Otherwise we can cast any object to any other - all are extending class Object :)
0
 
LVL 20

Expert Comment

by:Venabili
ID: 10732081
Read this for better understanding of inheritance:
http://java.sun.com/docs/books/tutorial/java/concepts/inheritance.html
0
 
LVL 37

Expert Comment

by:zzynx
ID: 10732131
Indeed.

imagine:

class Parent
{
  private String data;
}

class DerivedOne extends Parent
{
  private int dataOne;
}

class DerivedTwo extends Parent
{
  private String dataTwo;
}

DerivedOne d1 = new DerivedOne();

d1 has as members:
1) a String: data
2) an int: dataOne
     
DerivedTwo d2 = new DerivedTwo();

d2 has two members
1) a String: data
2) a String: dataTwo

It's clear that if you try cast d2 to a DerivedOne object, there's a problem with the 2nd data member.

0
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LVL 30

Expert Comment

by:Mayank S
ID: 10732162
>> Otherwise we can cast any object to any other - all are extending class Object

Correct. It will throw ClassCastExceptions. You can assign a reference to an object only if it is an instance of it. You can check it, to avoid the exception:

if ( d2 instanceof DerviedOne )
  d1 = ( DerviedOne ) d2 ; // end if

else
  System.out.println ( "d2 is not an instance of DerivedOne class. " ) ; // end if
0
 
LVL 14

Expert Comment

by:StillUnAware
ID: 10733631
this works:

public class Parent{
}

class DerivedOne extends Parent{
}

class DerivedTwo extends Parent{
}

class Test{
  public static void main (String args[]) {
    Parent p = new Parent();
    DerivedOne d1 = new DerivedOne();
    DerivedTwo d2 = new DerivedTwo();
    d1 =(DerivedOne)((Parent)d2);
  }
}  
0
 
LVL 14

Expert Comment

by:StillUnAware
ID: 10733652
First you upcast to base class Parent, then downcast to DerivedOne.
0
 
LVL 14

Expert Comment

by:StillUnAware
ID: 10733721
I am really sory for my unawareness, I made a mistake :). It won't  help you.
0
 
LVL 13

Expert Comment

by:Webstorm
ID: 10740030
You can do this:

class Test{
  public static void main (String args[]) {
    Parent p = new Parent(),
         d1 = new DerivedOne(),
         d2 = new DerivedTwo();
    d1 =d2;
  }
}  


0
 
LVL 30

Expert Comment

by:Mayank S
ID: 10740371
Guess that will throw a ClassCastException.
0
 
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Expert Comment

by:Mayank S
ID: 10740384
I mean: >> d1 =d2;
0
 
LVL 13

Expert Comment

by:Webstorm
ID: 10740500
No, because d1 and d2 are Parent instance reference and DerivedOne & DerivedTwo are subclass of Parent.
Have you tested it ?
0
 
LVL 13

Expert Comment

by:Webstorm
ID: 10740533
>> d1 and d2 are Parent
You probably not have seen the comma separating declarations of Parent references.

0
 
LVL 30

Expert Comment

by:Mayank S
ID: 10740555
>> You probably not have seen the comma separating declarations of Parent references

Right, I missed the comma :-)
0

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