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Using 'in' for an Array, not a Set

Posted on 2004-04-05
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Last Modified: 2010-04-05
Is it possible to use the 'in' operator to find if an integer is in an array of integer?

The boolean-resulting:

7 in [5, 7, 9]

... would return TRUE for instance. Can I do something similar like:

7 in aNumbers

where aNumbers is an array of integer? Or do I have to do an ugly looping checker against each aNumbers[x] from 0 to length(aNumbers)?

Please give reasons for your answer: no points for just the quickest person to type "nope"   ;-)

Martin
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Question by:MartinC
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4 Comments
 
LVL 27

Expert Comment

by:kretzschmar
ID: 10763370
defintivly no!

you need a function which loops through the array

meikl ;-)
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LVL 27

Expert Comment

by:kretzschmar
ID: 10763374
well, i need no points :-)))
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LVL 11

Accepted Solution

by:
ZhaawZ earned 240 total points
ID: 10763444
If working with strings, it could be AnsiMatchText() (case insensitive) or AnsiMatchStr() (case sensitive) from StrUtils.
Looping through array is not so ugly:

function IntegerInArray (number : integer; const arr : array of integer) : boolean;
var n : integer;
begin
for n := low(arr) to high(arr) do if arr[n] = number then break;
result := n <= high(arr);
end;
0
 

Author Comment

by:MartinC
ID: 10763922
Ah well, if Kretzschmar The Infallible just says "nope" i guess I have to accept it ... thanks for promptness! Given that Kretschmar has said he doesn't need the points and Zhaawh has saved me even writing the function, and i am an incredibly lazy person, i'm gonna give the points to Zhaawh.

Thanks to both!

Martin
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