Solved

HTML Resize image based on the TD width

Posted on 2004-04-07
10
757 Views
Last Modified: 2012-08-13
Can anyone please tell me how to increase the image size based on width.

I got a reply for this I am pasting the code below

 Comment from dgelinas
Date: 03/30/2004 05:33AM PST
 Comment  


sure,

</script>
function resizeImage() {
  document.getElementById('img1').width =  document.getElementById('td1').offsetWidth
}
<script>



  <td id='td1'>
  <img id='img1' src='/images/whatever.gif'>

 
Comment from dgelinas
Date: 03/30/2004 06:10AM PST
 Comment  


better yet here's a working test I used.. obviously you won't have my image but you can replace it with yours

<html>
<head>
<script language="javascript" type="text/javascript">
function resizeImage() {
  document.getElementById('img1').width =  document.getElementById('td1').offsetWidth
}
</script>

</head>

<body onLoad="resizeImage()">


<table width="183"  border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td id='td1'><img id='img1' src="logo2.gif" width="5" height="50"></td>
  </tr>
  <tr>
    <td></td>
  </tr>
</table>  

</body>
</html>
 
 
BUT THE ABOVE CODE works if there is one image and TD . I am generating images and TD dynamically. How should I go about doing this.

Please guide me.
0
Comment
Question by:BLN2004
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10 Comments
 
LVL 28

Expert Comment

by:peakpeak
ID: 10781679
Maybe like this ...

function resizeOneImage(imgname, tdid)
 {
  document.getElementById(imgname).width =  document.getElementById(tdid).offsetWidth
}

function getElementsById(imgname, id)
{
  var inc = 0;
  var alltags = document.all ? document.all : document.getElementsByTagName("*");
  for (i = 1; i < alltags.length; i++)
    if (alltags[i].id == id)
      reziseOneImage(imgname, id);
}
<body onload="getElementsById('img1', 'td1');" >
....
<td id='td1'><img id='img1' src="logo1.gif" width="5" height="50"></td>
<td id='td1'><img id='img1' src="logo2.gif" width="5" height="50"></td>
<td id='td1'><img id='img1' src="something_else.gif" width="5" height="50"></td>
....
</body>

Regards
Peter
0
 
LVL 28

Accepted Solution

by:
peakpeak earned 50 total points
ID: 10782081
Oops, forget my previous post, here's a working one
Select te same id for every <td> and <img>, different name for each <img>
onLoad="resizeImages('b');" with the <td> and <img> id

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<HEAD>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<SCRIPT type="text/javascript">
<!--
function resizeOneImage(imgname, tdid)
{
      document.getElementById(imgname).width =  document.getElementById(tdid).offsetWidth;
}
var fields = new Array();      // Global array for the field objects we want
////////////////////////////////////////////////
// Resize all images with a specific id
//
function resizeImages(id)
{
      var inc = 0;
      var alltags = document.all ? document.all : document.getElementsByTagName("*");
      for (i = 1; i < alltags.length; i++)
      {
            if (alltags[i].id == id)
            {
                  fields[inc++] = alltags[i];      // Save the object in the array
            }
      }
      for (i = 0; i < fields.length; i++)      
      {
            if (fields[i].name)
                  resizeOneImage(fields[i].name, id);
      }
      return inc;
}
//-->
</SCRIPT>
</head>
<BODY onLoad="resizeImages('b');">
<table width="280"  border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td id="b"><img id='b' name="img1" src="imgage1.gif"></td>
    <td id="b"><img id='b' name="img2" src="imgage2.gif"></td>
    <td id="b"><img id='b' name="img3" src="other.gif"></td>
  </tr>
</table>
</body>
</html>

Regards
Peter

0
 
LVL 7

Assisted Solution

by:TheKenman
TheKenman earned 50 total points
ID: 10783014
Hi BLN2004,

Try this:

   <html>
   <head>
   <script language="javascript">  
   function resiz() {
      var imgs = document.images;
      for(i=0;i<imgs.length;i++)
      {
      var img = imgs[i];
         if (document.all) {
            img.width = img.parentElement.width;
            img.height = img.parentElement.height;  
         } else {
            img.width = img.parentNode.width;
            img.height = img.parentNode.height;  
         }
      }
   }
   </script>  
   </head>
   <body onLoad="resiz();">
   <table width="183"  border="0" cellspacing="0" cellpadding="0">
     <tr>
       <td id='td1'><img id='img1' src="logo2.gif" width="5" height="50"></td>
     </tr>
     <tr>
       <td></td>
     </tr>
   </table>
   </body>
   </html>
0
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LVL 6

Expert Comment

by:Andy
ID: 10787979
Setting the width and height of the image to 100% means it will stretch and shrink to fit the table cell it occupies. As the user resizes their browser window your picture will resize automatically.
0
 

Author Comment

by:BLN2004
ID: 10820088
I tried the below code

<html>
<HEAD>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<SCRIPT type="text/javascript">
<!--
function resizeOneImage(imgname, tdid)
{
     document.getElementById(imgname).width =  document.getElementById(tdid).offsetWidth;
}
var fields = new Array();     // Global array for the field objects we want
////////////////////////////////////////////////
// Resize all images with a specific id
//
function resizeImages(id)
{
     var inc = 0;
     var alltags = document.all ? document.all : document.getElementsByTagName("*");
     for (i = 1; i < alltags.length; i++)
     {
          if (alltags[i].id == id)
          {
               fields[inc++] = alltags[i];     // Save the object in the array
          }
     }
     for (i = 0; i < fields.length; i++)    
     {
          if (fields[i].name)
               resizeOneImage(fields[i].name, id);
     }
     return inc;
}
//-->
</SCRIPT>
</head>
<BODY onLoad="resizeImages('b');">
<table width="280"  border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td id="b"><img id='b' name="img1" src="imgage1.gif"></td>
    <td id="b"><img id='b' name="img2" src="imgage2.gif"></td>
    <td id="b"><img id='b' name="img3" src="other.gif"></td>
  </tr>
</table>
</body>
</html>


THE IMAGE IS SMALL IN THE FIRST CELL SLOWLY IT INCREASSES IN THE LAST CELL IT FITS THE TD
0
 
LVL 7

Expert Comment

by:TheKenman
ID: 11938972
I recommend a split between peakpeak and myself :)
0

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