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A struct question

The question I found it from the text as following:
You are required to design, implement and test a function, sort_list(.), which will sort such a list according to the priority value computed by whatever function is passed as its second argument. The first argument is to be a pointer to the head of the list. Since the OS will have other structures with pointers to IORB's, the list must be sorted in place.

typedef struct iorb {
                        short base_pri;
                        struct iorb *link;
                        char filler[110];
                        } IORB;
void sort_list(IORB **list,int(*newpr)(short));
int newp(short base)
return base;
just want to know how to build up a list and how to insert a value.

1 Solution
From what I could gather, you will be given the list ... All you need to do is to get priorities and sort it

step 1. traverse the list (arg 1 ) ... for each element, get priority using function given as arg 2 ... store this value in the node's base_pri field

step2: sort the list in place
Hi fj8283888,

Sorting in-place of a linked list can be done by bubble sort, which is bad by means of having quadratic behaviour, but easy to implement.

The problem with priority queues is to have both a favourable insert and fetch behaviour.

O(n) for insert and O(1) for fetch is trivial - it's just a linked list where you insert a new node after the last node of equal or higher priority.

Probably the fastest way should be a binary tree with the smallest element (or highest priority) on top.

To build a list,you need a pointer for the start node.
Lets say the start node is p;

The first node insertion:
Allocate memory for node
//p=malloc(sizeof(struct iorb));
//Insert data into the node.
p->data=//ur data here
//Set next pointer to NULL for now.

The next time around,you allocate memory to append to this list.
i.e. create a new node,set the link pointer of the prev. node to point to this new node'

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