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Calling malloc twice or redefining array sizes?

Posted on 2004-04-16
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Last Modified: 2008-02-01
Hey all,
I'm just curios about the consequences of calling malloc twice or assigning an array to a new size.
lets say we have

char* a = new char[10];
....
a = new char[20];

or

char* a = (char*) malloc(10);
.....
a = (char*) malloc(20);

If we do the above is it necessary to call delete or free etc before the second assignment to release the memory of (char) length 10 or is this released by default?  I'm a bit confused about this whole memory management thing.
Thanks,
Stef
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Question by:stefarg
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4 Comments
 
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Accepted Solution

by:
jkr earned 85 total points
ID: 10846353
>>If we do the above is it necessary to call delete or free etc before the second assignment

Definitely. Otherwise, you'd create a memory leak.

>> is this released by default?

No. You are responsible for freeing memory when you no longer need it.
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Author Comment

by:stefarg
ID: 10846383
Ok, so how do I clear this up, can I do the following:

char* a = new char[10];
....
delete [] a;

a = new char[20];

Is that correct and free of memory leaks?
Thanks for your response,
Stef
0
 
LVL 44

Assisted Solution

by:Karl Heinz Kremer
Karl Heinz Kremer earned 40 total points
ID: 10846424
Yes, this is the right way to do it. It's important that you use the "[]" form of delete if you allocated an array with new.
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Author Comment

by:stefarg
ID: 10846531
That's great, thanks
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