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returned values in ANSI C

Posted on 2004-04-18
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Last Modified: 2011-09-20
Well I'm not the best when it comes to ANSI C programming...but i thought this was for sure.
Let's say we have the code

#include <stdio.h>

int test()
{
     return 1;

}

void main()
{
     int t;
     t=test();
     printf("t=%d\n", &t);
}

I expected that the output at the screen would be "t=1"....It's not it's something like 1245052 and doen't seem somehow connected to the value the test() functin returns...
The problem is how can I save the value that a function returns into a variable...In this specific case how can I save somewhere the value "1".
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Question by:jonn_g
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Accepted Solution

by:
Karl Heinz Kremer earned 200 total points
ID: 10852738
This has nothing to do with the return value, the problem is that you are passing the address of t to the printf function, and not t. Use this:

printf("t=%d\n", t);

You probably got this confused with scanf, which needs and address so that the value of the variable can actually be modified. You need to understand the difference between "pass by value" and "pass by reference"
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LVL 44

Expert Comment

by:Karl Heinz Kremer
ID: 10852742
... and just in case it's not clear, the value "1" was already correctly saved in the "t" variable.
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