Solved

Email Client/Server App. - FileName

Posted on 2004-04-21
5
155 Views
Last Modified: 2010-03-31
i have an array of user entered file paths that i store in files[]
then when i want to send i do the following...
 
 File f = new File(files[i]);
 
How do i get the name of the file now from f ?

Thanks

0
Comment
Question by:tricks801
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
5 Comments
 
LVL 92

Accepted Solution

by:
objects earned 400 total points
ID: 10884547
String name = f.getName();
0
 

Author Comment

by:tricks801
ID: 10884561
thanks
0
 
LVL 92

Expert Comment

by:objects
ID: 10884591
have a look at the the javadoc for any otyher methods your require:

eg.

 File getAbsoluteFile()
          Returns the absolute form of this abstract pathname.
 String getAbsolutePath()
          Returns the absolute pathname string of this abstract pathname.
 File getCanonicalFile()
          Returns the canonical form of this abstract pathname.
 String getCanonicalPath()
          Returns the canonical pathname string of this abstract pathname.
 String getName()
          Returns the name of the file or directory denoted by this abstract pathname.
 String getParent()
          Returns the pathname string of this abstract pathname's parent, or null if this pathname does not name a parent directory.
 File getParentFile()
          Returns the abstract pathname of this abstract pathname's parent, or null if this pathname does not name a parent directory.
 String getPath()
          Converts this abstract pathname into a pathname string.
0
 
LVL 23

Assisted Solution

by:rama_krishna580
rama_krishna580 earned 100 total points
ID: 10884784
f.getAbsoluteFile()
f.getAbsolutePath()
f.getCanonicalFile()
f.getCanonicalPath()
f.getName()
f.getParent()
f.getParentFile()
f.getPath() ............etc......

......here is the example code you can use it...........to find out the details...

                        System.out.println();
                        System.out.println("*************************************************************");

                        System.out.println("getName()          = " + f.getName());
                        System.out.println("getAbsoluteFile().getName() = " + f.getAbsoluteFile().getName());

                        boolean exists = f.exists();
                        if(exists)
                              System.out.println("Exists()           = " + exists);
                        else
                              System.out.println("Does not exists()           = " + exists);


                        if (!exists) { System.exit(1);  }

                        System.out.println("canRead()          = " + f.canRead());
                        System.out.println("canWrite()         = " + f.canWrite());
                        System.out.println("getPath()          = " + f.getPath());
                        System.out.println("getAbsolutePath()  = " + f.getAbsolutePath());
                        System.out.println("getCanonicalPath() = " + f.getCanonicalPath());
                        System.out.println("getAbsoluteFile()  = " + f.getAbsoluteFile());
                        
                        // External Usage Options
                        //System.out.println("toURL()            = " + f.toURL());
                        //System.out.println("toURI()            = " + f.toURI());

                        System.out.println("getParent()        = " + f.getParent());
                        System.out.println("isAbsolute()       = " + f.isAbsolute());

                        boolean isDirectory = f.isDirectory();
                        if(isDirectory)
                              System.out.println("isDirectory()      = " + isDirectory);
                        else
                              System.out.println("isNotDirectory()   = " + isDirectory);
                        
                        boolean isFile = f.isFile();
                        if(isFile)
                              System.out.println("isFile()           = " + isFile);
                        else
                              System.out.println("isNotFile()        = " + isFile);

                        System.out.println("isHidden()         = " + f.isHidden());
                        System.out.println("lastModified()     = " + (d = f.lastModified()) + " = " + new Date(d));
                        System.out.println("length()           = " + f.length());

                        if (isDirectory)
                        {
                              String[] subfiles = f.list();
                              
                              for (int i=0; i < subfiles.length; i++)
                              {
                                    System.out.println("File in this Dir   = " + subfiles[i] );
                              }
                        }

                        System.out.println("*************************************************************");
                        System.out.println();
0
 
LVL 92

Expert Comment

by:objects
ID: 10894569
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
type mismatch (Object[] to double[] 4 41
hibernate example for saving data 19 76
CSV file parsing thru Java 13 39
Glassfish admin console not working 1 56
By the end of 1980s, object oriented programming using languages like C++, Simula69 and ObjectPascal gained momentum. It looked like programmers finally found the perfect language. C++ successfully combined the object oriented principles of Simula w…
Java functions are among the best things for programmers to work with as Java sites can be very easy to read and prepare. Java especially simplifies many processes in the coding industry as it helps integrate many forms of technology and different d…
This video teaches viewers about errors in exception handling.
This tutorial will introduce the viewer to VisualVM for the Java platform application. This video explains an example program and covers the Overview, Monitor, and Heap Dump tabs.

749 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question