Hey man. I wanted to write a program to process simple algebra problems..
like:
3x + 15 = 11 - x
4x = -4
x = -1
how would you suggest going about this? I dont plan to write it in C, I was acctually going to write it in Visual Basic, but you are good with math, so I was curious how you would suggest doing it. So far I've created a type structure array to store all the monomials, but how do you suggest processing it, I'm stumpted. If you want to throw out some C code, I can port it to VB.
Right now I am going to focus on Single Variables.
0
Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.
If your problems will all be single variable linear equations you could just change = to -
evaluate at two x values, then extrapolate to where the expression equals 0
To make it simple (e.g. without going to RPN resolution etc...) you have to get 4 variables
v1 is the number of x on left side
v2 is the number on left side (no x)
v3 is the number of x on right side
v4 is the number on right side (no x)
e.g. for 3x + 15 = 11 - x
v1 = 3
v2 = 15
v3 = -1
v4 = 11
The you calculate
vx = v1 - v3
vn = v4 - v2
And you have your result R = vn / vx
vx = v1 - v3 = 4
vn = -4
R = 4 / -4 = -1
How to proceed programmatically (automat)
1 - initialize all v1,v2,v3,v4 to 0.
2 - parse the equation left side for v1, v2
3 - set default sign is "+"
4 - you get a sign : set sign to + or -
5 - you get a number : put the number in N
6 - number is followed by x : do v1 = v1 + N
7 - number is not followed by x : do v2 = v2 + N
8 - repeat from 3 etc...
Do the same right side, the vars being v3,v4
Once you get all v1...v4, calculate R as above.
of course of steps 5 and 6, N is signed by 'sign' (ie N = N * sign ), sign being 1 if "+", -1 if "-"
0
Featured Post
Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.