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pdf read

Posted on 2004-04-25
17
354 Views
Last Modified: 2010-04-01
Hi Experts,

I am reading pdf using bits .....sometime bit is different it can be 1024 / 2048 etc ...How to find out this attribute before processing file ?

Thank you.
0
Comment
Question by:fpoyavo
  • 10
  • 6
17 Comments
 
LVL 1

Author Comment

by:fpoyavo
ID: 10913282
I have found this code ... can it be useful ?

<code>
import java.io.*;
import javax.print.*;
import javax.print.attribute.*;
import javax.print.attribute.standard.*;

public class Print {

public Print()
{}

public static void main(String[] args)
{
// PrintDoc is an implementation of Doc
Doc pdoc = new PrintDoc("file.ps");

// Gets the format of the document
DocFlavor flavor = pdoc.getDocFlavor();

// Creates a new attribute set
PrintRequestAttributeSet aset = new HashPrintRequestAttributeSet();

// Locates default printer to print the specified document format
// with the specified attribute set
PrintService service = PrintServiceLookup.lookupDefaultPrintService();

if (service != null) {
DocPrintJob job = service.createPrintJob();

try {
job.print(pdoc, aset);
}
catch (PrintException pe) { }
}
}
}

class PrintDoc implements Doc {
private String filename;
private InputStream stream;

public PrintDoc(String fname)
{
this.filename = fname;
}
public DocFlavor getDocFlavor() {
return DocFlavor.INPUT_STREAM.AUTOSENSE;
}

// No attributes attached to this Doc - mainly useful for MultiDoc
public DocAttributeSet getAttributes() {
return null;
}

// Since the data is to be supplied as an InputStream delegate
// to getStreamForBytes().
public Object getPrintData() throws IOException {
return getStreamForBytes();
}

// Not possible to return as text
public Reader getReaderForText() throws UnsupportedEncodingException, IOException {
return null;
}

// Return the print data as an InputStream.
// Always return the same instance.
public InputStream getStreamForBytes() throws IOException {
synchronized(this) {
if (stream == null) {
stream = new FileInputStream(filename);
}
return stream;
}
}
}
</code>
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10913343
I have :

byte[] buf = new byte[2048];
                int nread = 0;
                 while (-1!=(nread=in.read(buf)))
                 {
                   outf.write(buf, 0, nread);
                 }

May be there is some way to find out that file has to be read as 1024 ????
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10913518
it does not really make a diff for you to read it in 1028 chunks or 2048 chunks...
both shd be working....

you can use, nread.available() method to find out the available bytes to read...
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LVL 1

Author Comment

by:fpoyavo
ID: 10913647
Kudleep,

Please more details. :) I know you are busy but please.

Thank you.
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10913696
you can read your stream in different ways...

one can be
//read one byte at a time

byte buf = new byte[2048];
                int nread = 0;
                 while (-1!=(buf=in.read()))
                 {
                   outf.write(buf);
                 }
//slow but reliable

you can read all at one time
byte[] buf = new byte[in.available()];
                int nread = in.available();
                 outf.write(buf, in.read(buf), nread);
                 }

//fast but some times jumps if the stream is not ready by the time we execute in.available();

or you can read in it chucks of 1 K

byte[] buf = new byte[2048];
                int nread = 0;
                 while (-1!=(nread=in.read(buf)))
                 {
                   outf.write(buf, 0, nread);
                 }

so its up to you..
I usually use the first one becoz its most reliable

0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10913776
Hi Kudeep,

This is great :

byte[] buf = new byte[in.available()];
                int nread = in.available();
                 outf.write(buf, in.read(buf), nread);
                 }

How I can do delay 1 sec here before ...because it looks like it is too fast ?
And ...shouldit be while here ? or } just a typo ?

Thank you very much.
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10913786
don't need a why here because we are reading everything available on the stream in one go....:-)
putting a 1 sec delay ruines the whole gain that you get in the performance so I do not suggest that....
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10913814
iT SEEMS that stream is not ready by the time we execute in.available :( ???? What is next ?
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10913819
Have you tried other two variations that I have written???
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10914306
Yep.

The first one gave me : Incompatible type for declaration. Can't convert byte[] to byte.
in byte buf = new byte[2048];

The second one gives error opening pdf from jsp and if I do it directly.

The third one the I used and process fine pdfs that have 2048 when I have byte[2048] but those having 1024 message "damaged file" is displayed.
WheN I change it to byte[1024] it process fine pdfs with 1024 but has problem with those having 2048.

Please help.
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10914308
Is there way to find out if file has 1024 or  2048 ?
0
 
LVL 23

Accepted Solution

by:
rama_krishna580 earned 500 total points
ID: 10914564
try this,.,


res.setContentType("application/pdf");
ServletOutputStream out = res.getOutputStream();

//The filename is passed in as a parameter;
String sFileName = (String)req.getParameter("filename");

// Override the filename for testing.
sFileName="myReport.pdf";

try {
File file = new File(sFileName);

byte[] byteContents = new byte[(int)file.length()];

FileInputStream in = new FileInputStream(sFileName);

// Read the file.
int retcd = in.read(byteContents);

// Read past end of file.
// retcd = in.read(byteContents);

in.close();

out.write(byteContents);
out.flush();
out.close();


res.setContentType("application/pdf");
//res.setStatus(res.SC_OK);
return;
}
catch (Exception e)
{
System.out.println(">>>> srvletDownloadPDF exception: " + e);
//res.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR,e.toString());
return;
}

R.K
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10914682
Rama,

I got this : Undefined variable or class name: file
                byte[] byteContents = new byte[(int)file.length()];
pointing to file.length ????
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10914742
Ok...It writes file but due to errors it cannot be opened.
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10914881
All the time I was thinking that you are getting the file from a URL..!! and not from disk....
0
 
LVL 1

Author Comment

by:fpoyavo
ID: 10924445
You are right I am getting it from URL but I used your technique Kudleep (thank you for this) and works fine for URL or regular file.
Rama was close because the only thing I have missed was close files and trying to open them again later in my logic.

Thank you bro.  
0
 
LVL 19

Expert Comment

by:Kuldeepchaturvedi
ID: 10924561
:-)
got that, I was wondering...... Thanks for clarifying
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