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Checking if a string contains a letter in ksh

Posted on 2004-04-26
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Last Modified: 2007-12-19
Hi, I'd like to check a string for the presence of letters.

E.g.

"123" valid
"abc" invalid
"123abc"  invalid

At the moment I don't know how to check when a string has both a number and a letter; it just crashes out.

My current code is as follows:

i=1
until (test $i -gt 4)
do
  echo "$arg1"|cut -f$i -d'.'|read octet
  if [[ "$octet" = +([a-z]) ]]
  then
    echo "Error - invalid IP address entered"
    IPvalid=0
    i=4
  else
    if [[ $octet -ge 0 && $octet -le 255 ]]
    then
      IPvalid=1
    else
      echo "Error - invalid IP address entered"
      IPvalid=0
      i=4
    fi
  fi
  i=`expr $i + 1`
done

Thanks

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Question by:r47463
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  • +1
8 Comments
 

Author Comment

by:r47463
ID: 10923312
PS rather than just letters, I would like any non-numeric characters to be invalid.
0
 
LVL 28

Expert Comment

by:FishMonger
ID: 10924787
Would you be interested in using Perl instead of ksh?

#!/usr/bin/perl -w

use strict;
use Validate::Net;

my $good = '123.1.23.123';
my $bad1 = '123.432.21.12';
my $bad2 = 'abc.232.21.12';

foreach ( $good, $bad1, $bad2 ) {
   if ( Validate::Net->ip( $_ ) ) {
      print "'$_' is a valid ip\n\n";
   }
   else {
      print "'$_' is not a valid ip address because:\n";
      print Validate::Net->reason . "\n\n";
   }
}


-- outputs --
'123.1.23.123' is a valid ip

'123.432.21.12' is not a valid ip address because:
The maximum value for an ip element is 255

'abc.232.21.12' is not a valid ip address because:
Does not fit the basic dotted quad format for an ip
0
 
LVL 28

Expert Comment

by:FishMonger
ID: 10924822
That code sample is from the CPAN documentation for the Validate::Net module.

http://search.cpan.org/~adamk/Validate-Net-0.5/lib/Validate/Net.pm
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LVL 9

Expert Comment

by:bhagyesht
ID: 10925105
Hi r47463,
use isnumeric function to determine whether its a number or not

Cheers!
0
 
LVL 45

Expert Comment

by:sunnycoder
ID: 10925274
[!0-9] represents all non numeric characters .. 0-9 is the range for numeric characters and ! is negation
0
 
LVL 9

Expert Comment

by:bhagyesht
ID: 10926896
sorry wrongly interpreted it for VB.

Regards,
Bhagyesh
0
 
LVL 45

Accepted Solution

by:
sunnycoder earned 40 total points
ID: 10927170
>At the moment I don't know how to check when a string has both a number and a letter; it just crashes out.

execute this

echo $u | grep "[^0-9]" >dev/null
then check for value of $? ... If 1 then it was composed of characters from 0-9

if [ $? -eq 1 ]
then
          echo valid
else
          echo invalid
fi
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Author Comment

by:r47463
ID: 10932270
Superb thanks!
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