Solved

# Doble array execution

Posted on 2004-04-27

I am trying to find the array that results from the execution of (3, 4, 21)

Where the code for the method that was given to me is:

public static int [] [] f(int n, int m, int value);

{

int [] [] x = new int [n] [m];

for (int i=0; i < x.lenght; i++)

for (int j = 0; j < x[i].lenght; j++)

x[i] [j] = value;

return x;

}

Down below you can find how tried to run it.... I am missing something but do not know what. Can someone help me with this? Thank you! J.Cisek - Java student.

public class SkillBuilder

{

int [] [] f(int n, int m, int value);

public static void main(String[] args)

{

int [][] x = new int [n] [m];

for (int i=0; i < x.lenght; i++)

for (int j = 0; j < x[i].lenght; j++)

x[i] [j] = value;

return x;

}

System.out.println( x (x(int n, int m, int value) ) );