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Get Current Mixer Volume (vb.net)

Posted on 2004-04-27
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Last Modified: 2012-06-27
I am trying to display the current volume level of audio playing on my computer.

Not the level to which the volume is set, but the level (how loud) the audio that is currently playing is.

To further simplify, I really just need to get a boolean which tells me whether or not there is any sound playing on the system.

This needs to be a .net solution (any .net language is fine) ... There are many solution in MSDN and on the internet using windows api's to return a mixer but none of them appear to work with Windows XP and .net.

Thanks in advance.

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Question by:KeirGordon
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7 Comments
 
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Expert Comment

by:gregoryyoung
ID: 10935254
Are you familiar with how to call a .dll from .net ?

I would suggest reading http://msdn.microsoft.com/library/default.asp?url=/library/en-us/cpguide/html/cpconcallingdllfunction.asp and then using the API functions to call the API methods
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by:gregoryyoung
ID: 10935256
err using the API methods

*do what I say not what I type*
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Author Comment

by:KeirGordon
ID: 10939663
Yes, i've tried GetWaveOutVolume, and GetWaveOutPitch, and a mass of other functions available in the winmm.dll but none are helping me... what i've tried atleast only works when you open the waveout programatically..... but is not useful if you are trying to see if any other application is playing audio.   Just need to know if there is any audio playing at all, maybe a way to see the number of currently open wave devices or something?
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Accepted Solution

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gregoryyoung earned 500 total points
ID: 10940160

http://support.microsoft.com/default.aspx?scid=kb;en-us;181550

shows how to do it in C++ call the same API calls from .net
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Author Comment

by:KeirGordon
ID: 10952613
As I was saying, those API's do not work with windows XP.  I don't know exactly why.  But i d/l and ran that executable and it gives no reading.  I tried on several machines.

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Expert Comment

by:gregoryyoung
ID: 10978787
I'm running XP and they worked fine here.
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Author Comment

by:KeirGordon
ID: 10979097
I was working with the MSDN code you posted, I have no trouble opening the mixer, but I can not open the line:

    mxl.dwComponentType = MIXERLINE_COMPONENTTYPE_SRC_WAVEOUT;

    rc = mixerGetLineInfo(( HMIXEROBJ )hMixer, &mxl, MIXER_GETLINEINFOF_COMPONENTTYPE);
    if (MMSYSERR_NOERROR == rc) {
       printf("couldn't open line");
    }

I also tried opening the DST_WAVEIN line.
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