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Record paging with JSP

Posted on 2004-04-27
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Last Modified: 2007-12-19
I want to display the recors with paging like google.

There will huge no of records and i want to display only 10 records in a single page.The rest records will be displayed into the same page with the paging numbers.

Plz provide me the code
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Question by:bappa_chow
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4 Comments
 
LVL 32

Expert Comment

by:ldbkutty
ID: 10935933
JSP Paging:
http://jsptags.com/tags/navigation/pager/index.jsp
http://jsptags.com/tags/navigation/pager/pager-taglib-2.0.html

But, i am using PAGING from a different application...i have described my application below....its your wish to understand this or to use the above link applications.

My appliation displays 10 Records per page and displays next/previous page...and use what you want from it...

    int iCounter=0;
    int iPage = 0;
    boolean bIsScroll = true;
    String sSQL="";
    String sPage = "";
    int RecordsPerPage = 10;
  // Build full SQL statement
 
  sSQL = "select n.field1 as n_field from tablename n;
 
  String sNoRecords = "     <tr>\n      <td > NO RECORDS </font></td>\n     </tr>";
  out.println("    <table> ");
     
  try {
    // Select current page
    iPage = Integer.parseInt(request.getParameter("FormNews_Page"));
  }
  catch (NumberFormatException e ) {
    iPage = 0;
  }

  if (iPage == 0) { iPage = 1; }
  RecordsPerPage = 10;
  try {
    java.sql.ResultSet rs = null;
    // Open recordset
    rs = openrs( stat, sSQL);
    iCounter = 0;
    absolute (rs, (iPage-1)*RecordsPerPage+1);
    java.util.Hashtable rsHash = new java.util.Hashtable();
    String[] aFields = getFieldsName( rs );

    // Show main table based on recordset
    while ( (iCounter < RecordsPerPage) && rs.next() ) {

      getRecordToHash( rs, rsHash, aFields );
      String fldfield1 = (String) rsHash.get("n_field1");
 
      out.println("     <tr>");
      // Display the fields here
      out.print("</tr>");
   
      iCounter++;
    }
    if (iCounter == 0) {
      // Recordset is empty
      out.println(sNoRecords);
      bIsScroll = false;
    }

    else {
    // Parse scroller
    boolean bInsert = false;
    boolean bNext = rs.next();
    if ( !bNext && iPage == 1 ) {
   
      out.print("     <tr>\n      <td>\n  ");
      out.println("\n      </td>\n     </tr>");
   
    }
    else {
      out.print("     <tr>\n      <td>");
      bInsert = true;
   
      if ( iPage == 1 ) {
        out.print("\n       <a href_=\"#\"><font style=\"font-size: 10pt; color: #000000; font-weight: bold\">Previous</font></a>");
      }
      else {
        out.print("\n       <a href=\""+sFileName+"?FormNews_Page="+(iPage - 1)+"#Form\"> Previous </a>");
      }
 
      out.print("\n       [ "+iPage+" ]");
 
      if (!bNext) {
        out.print("\n       <a href_=\"#\"> Next </a><br>");
      }
      else {
        out.print("\n       <a href=\""+sFileName+"?"+"FormNews_Page="+(iPage + 1)+"#Form\"><font style=\"font-size: 10pt; color: #000000; font-weight: bold\">Next</font></a><br>");
      }
   
      if ( ! bInsert ) {
        out.print("     <tr>\n      <td colspan=\"2\" style=\"background-color: #FFFFFF; border-style: inset; border-width: 1\"><font style=\"font-size: 10pt; color: #000000; font-weight: bold\">");
       }
   
      out.println("</td>\n     </tr>");
    }
 
    }

    if ( rs != null ) rs.close();
    out.println("    </table>");
   
  }
  catch (Exception e) { out.println(e.toString()); }

AND ---->


   /**
  * Absolute function
  */
  public static void absolute(java.sql.ResultSet rs, int row) throws java.sql.SQLException{
    for(int x=1;x<row;x++) rs.next();
  }
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LVL 32

Accepted Solution

by:
ldbkutty earned 50 total points
ID: 10953312
Hello,

Jut came across this application, which is much more easier...you can have a look...

http://www-106.ibm.com/developerworks/db2/library/techarticle/0307balani/0307balani.html

Tell me if u r succesful...

All the Best.
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