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How to move data from char** to char* ?

Posted on 2004-04-28
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Last Modified: 2012-05-04
I have a function "func_a" that returns me a pointer to some data as follows:

extern void func_a(char **data);

char *mydata ;
func_a(&mydata);

extern void func_b(char *data);

How do I pass in the data "mydata" that is returned by "func_a" into "func_b"  correctly?
Can I use sizeof(mydata) to get the size of data being returned?

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Question by:pcssecure
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3 Comments
 
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sunnycoder earned 1500 total points
ID: 10936274
Hi pcssecure,
> How do I pass in the data "mydata" that is returned by "func_a" into "func_b"  correctly?
The return type of func_a is void !!! Perhaps the return value is being set in the function using char ** ... is that correct ?

If yes, then func_b(mydata) should suffice for calling with updated value

Sunnycoder
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LVL 45

Expert Comment

by:sunnycoder
ID: 10936286
pcssecure,

sizeof(mydata) will evaluate to sizeof(char *) which will be constant irrespective of what the value held in the pointer is ... If it is a string, you can use strlen() to determine the length of the data ... If it is binary data, then you will have to use a separate integer value (returned from func_a) to keep track of the length

Sunnycoder
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Author Comment

by:pcssecure
ID: 10936584
yes, the return value is being set in the function char**.
The data concerned is binary.  I guess returning an integer value to keep track of length is the only way to get the size of binary data.
Thanks.
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