Solved

Java RegEx Question

Posted on 2004-04-28
10
386 Views
Last Modified: 2010-03-31
I want to build a regular expression that will let me know if a standalone 0 is in the string.  For example, I have the following string:

1 3 10 88 100 0 56
OR
0 4 10 20 45 1000
OR
2 10 44 60 100 0

The regular expression should return true on a match for a standalone 0.  However the string below should return false:

10 35 40 100

Thanks.
0
Comment
Question by:pcarrollnf
  • 4
  • 3
  • 2
  • +1
10 Comments
 
LVL 14

Expert Comment

by:Tommy Braas
ID: 10943784
" 0 "
0
 
LVL 14

Expert Comment

by:Tommy Braas
ID: 10943785
Note the spaces on either side of the 0
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 10943801
Pattern p = Pattern.compile("\\s+?0\\s+?");
Matcher m = p.matcher(input);
boolean gotLoneZero = m.find();
0
 

Author Comment

by:pcarrollnf
ID: 10943842
That doesn't appear to work.  You have to also keep in mind that the 0 may be the first digit in the string where it will not have any leading spaces and it may be the last digit where it will not have trailing spaces.  It also may be a part of another number such as 10 where it is valid.  So I guess there are 3 scenarios that should fail:

0 1 2
1 2 0
1 0 2

Each number will have a space before the next number unless it is the last one in the string.
0
 
LVL 86

Accepted Solution

by:
CEHJ earned 50 total points
ID: 10943864
Try

("^0\\s+?|\\s+?0\\s+?|\\s+?0$");
0
Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

 
LVL 92

Expert Comment

by:objects
ID: 10943961
Pattern p = Pattern.compile("\\s+?0\\s+?");
Matcher m = p.matcher(" "+input+" ");
boolean foundit = m.find();
0
 
LVL 14

Expert Comment

by:Tommy Braas
ID: 10943992
"(^0 | 0 | 0$)"
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 10944029
Identical to mine - only less tolerant of number of spaces
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 10944146
8-)
0
 
LVL 92

Expert Comment

by:objects
ID: 10944149
> Identical to mine - only less tolerant of number of spaces

Identical but functions differently, interesting concept :-D
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
firstswap challenge 20 68
Free Alternative to JIRA 4 91
maven example error 3 53
what is a "java.lang.System Property"   ? 20 57
After being asked a question last year, I went into one of my moods where I did some research and code just for the fun and learning of it all.  Subsequently, from this journey, I put together this article on "Range Searching Using Visual Basic.NET …
Introduction This article is the first of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article explains our test automation goals. Then rationale is given for the tools we use to a…
Viewers will learn about if statements in Java and their use The if statement: The condition required to create an if statement: Variations of if statements: An example using if statements:
Viewers will learn about the regular for loop in Java and how to use it. Definition: Break the for loop down into 3 parts: Syntax when using for loops: Example using a for loop:

863 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

20 Experts available now in Live!

Get 1:1 Help Now