pcarrollnf
asked on
Java RegEx Question
I want to build a regular expression that will let me know if a standalone 0 is in the string. For example, I have the following string:
1 3 10 88 100 0 56
OR
0 4 10 20 45 1000
OR
2 10 44 60 100 0
The regular expression should return true on a match for a standalone 0. However the string below should return false:
10 35 40 100
Thanks.
1 3 10 88 100 0 56
OR
0 4 10 20 45 1000
OR
2 10 44 60 100 0
The regular expression should return true on a match for a standalone 0. However the string below should return false:
10 35 40 100
Thanks.
Tommy Braas
" 0 "
Note the spaces on either side of the 0
Pattern p = Pattern.compile("\\s+?0\\s
Matcher m = p.matcher(input);
boolean gotLoneZero = m.find();
Matcher m = p.matcher(input);
boolean gotLoneZero = m.find();
ASKER
That doesn't appear to work. You have to also keep in mind that the 0 may be the first digit in the string where it will not have any leading spaces and it may be the last digit where it will not have trailing spaces. It also may be a part of another number such as 10 where it is valid. So I guess there are 3 scenarios that should fail:
0 1 2
1 2 0
1 0 2
Each number will have a space before the next number unless it is the last one in the string.
0 1 2
1 2 0
1 0 2
Each number will have a space before the next number unless it is the last one in the string.
ASKER CERTIFIED SOLUTION
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Pattern p = Pattern.compile("\\s+?0\\s
Matcher m = p.matcher(" "+input+" ");
boolean foundit = m.find();
Matcher m = p.matcher(" "+input+" ");
boolean foundit = m.find();
"(^0 | 0 | 0$)"
Identical to mine - only less tolerant of number of spaces
8-)
> Identical to mine - only less tolerant of number of spaces
Identical but functions differently, interesting concept :-D
Identical but functions differently, interesting concept :-D