Solved

from XML doc to DTD

Posted on 2004-04-29
4
244 Views
Last Modified: 2013-11-19
how to convert from XML document to DTD using jbuilder
i do the fooling but not yet could solve the problem

this program convert from db to xml (supposed to do that)

 out.write("<" + el.getNodeName() + ">");
          out.flush();

          for (int r = 0; r < tablesinfo[b].tsize; r++) {
            System.out.println("\n - r = " + r);
            System.out.println("\n - table parent = " +
                               tablesinfo[b].columns[r].parent);

            if (tablesinfo[b].columns[r].parent.compareTo(tablesinfo[b].tname) ==
                0) {
              if (tablesinfo[b].columns[r].ctype.compareTo("ID") == 0) {
                Attr attr = doc.createAttribute(tablesinfo[b].columns[r].cname);
                attr = el.setAttributeNode(attr);
                out.print("<" + tablesinfo[b].columns[r].cname + ">");
                out.flush();
                out.print("</" + tablesinfo[b].columns[r].cname + ">");
                out.flush();

              }
              else {
                // Create Table's original columns NODES!
                Element c = doc.createElement(tablesinfo[b].columns[r].cname);
                el.appendChild(c);
                out.print("<" + c.getNodeName() + ">");
                out.flush();
                out.print("</" + c.getNodeName() + ">");
                out.flush();

                Node parent = c.getParentNode();
                c = (Element) parent;
              }
            }
            else {
              // Create NEST Node's Nodes...
              nest[countnest] = tablesinfo[b].columns[r].parent;
              System.out.print(" - Subelement#" + countnest + nest[countnest] +
                               "has cols : ");
              countnest++;
              sube = doc.createElement(nest[countnest - 1]);
              el.appendChild(sube);
              out.print("<" + sube.getNodeName() + ">");
              out.flush();

              do {
                System.out.println("- Col#" + r + " is :" +
                                   tablesinfo[b].columns[r].cname);
                Element c = doc.createElement(tablesinfo[b].columns[r].cname);
                sube.appendChild(c);
                out.print("<" + c.getNodeName() + ">");
                out.flush();
                out.print("</" + c.getNodeName() + ">");
                out.flush();
                r++;
              }
              while ( (r < tablesinfo[b].tsize) &&
                     (tablesinfo[b].columns[r].
                      parent.compareTo(nest[countnest - 1]) == 0));
              out.print("</" + sube.getNodeName() + ">");
              out.flush();
              r--;
            }

          }
          out.write("</" + el.getNodeName() + ">");
          out.flush();
        }
      }

      out.print("</" + rootEl.getNodeName() + ">");
      out.flush();
      out.close();
    }

    catch (Exception e) {
      e.printStackTrace(System.err);
    } //end catch
  }
0
Comment
Question by:ousa
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
4 Comments
 

Accepted Solution

by:
joshuasherlock earned 125 total points
ID: 11012009
If you just want to create a one off DTD based on the XML you can try XMLSPY 2004 (www.altova.com). this will auto generate a DTD for you. However, as you are decided the format of the XML programatically you could write a generic DTD that defines the format that you expect your program to produce.

Another alternative is to use XSLT and your databases XML extensions (for example, the Oracle XDK with XSQL). First, you would  to extract the data from the database in a standard XML format then use XSL to transform the XML into your desired format. Would reduce the amount of coding needed but would require a bit of a learning curve on XSLT.

With more information on the nature of the problem I may be able to be more specific
0
 

Expert Comment

by:joshuasherlock
ID: 11709867
Thanks Modulo
0

Featured Post

Announcing the Most Valuable Experts of 2016

MVEs are more concerned with the satisfaction of those they help than with the considerable points they can earn. They are the types of people you feel privileged to call colleagues. Join us in honoring this amazing group of Experts.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

SASS allows you to treat your CSS code in a more OOP way. Let's have a look on how you can structure your code in order for it to be easily maintained and reused.
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
This theoretical tutorial explains exceptions, reasons for exceptions, different categories of exception and exception hierarchy.
The viewer will learn the benefit of using external CSS files and the relationship between class and ID selectors. Create your external css file by saving it as style.css then set up your style tags: (CODE) Reference the nav tag and set your prop…
Suggested Courses

636 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question