DOS equivalent to Unix “export” command?

I am using Windows 2000’s Paleolithic batch programming language to set environment variables and pass them along to an executable (VB, MSAccess).

I am using this in a .BAT file:

Set MyVar=ThisIsWhatIWantToReadWithEnviron
Echo %MyVar%

So that sets the variable, but it’s only alive inside the batch file.

Then I need to fire up a program that does this in VB:

Dim MyVar as String
MyVar = Environ$(“ ThisIsWhatIWantToReadWithEnviron”)
MsgBox "Environ returned: " & MyVar

But the variable is empty.

Unix has a command “export” to push an environment variable out to other shells and executables.

Is there a DOS equivalent?

Thanks!
geekboystevesAsked:
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Droby10Connect With a Mentor Commented:
also...

----
Set MyVar=ThisIsWhatIWantToReadWithEnviron
----
MyVar = Environ$(“ ThisIsWhatIWantToReadWithEnviron”)
----

wouldn't the second line need to be:

MyVar = Environ$("MyVar")

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Droby10Commented:
"Unix has a command “export” to push an environment variable out to other shells and executables."

sort of.  export publishes an environment variable for inheritance by _child_ processes, and the same principal applies in windows.  however, windows environment variables are not segmented in this fashion, all are inherited, so the set command is all that is needed to accomplish both tasks.  any application started from within that dos/cmd batch script (or even the controlling shell in most cases), would inherit your desired environment.  it's just not a global environment where you can run the script and then double click the executable - because it would receive it's environment from explorer instead.

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geekboystevesAuthor Commented:
Whoops.  Of course you are right (see "also..." above) about my erroneous example code.  The reason it was not working for me was that in my batch file I had spaces on either side of the "=" in the Set command and that made the Set statement fail.  Once I removed the spaces (as shown here, but not in my actual code) my VB program regurgitated the values using Environ$() just fine.

Thanks for the speedy reply!
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