Want to avoid the missteps to gaining all the benefits of the cloud? Learn more about the different assessment options from our Cloud Advisory team.
Solved
Format data from a file
Posted on 2004-05-02
In my code, I read data from a file..here are the first 2 lines...
990102
030901
I stored each line and what I want to do is put it in this format:
01/02/99
09/01/03
Basically, what I want to do is scan through the buffer (where I stored the line), and put them in that format.
How would I do this?
990102
030901
I stored each line and what I want to do is put it in this format:
01/02/99
09/01/03
Basically, what I want to do is scan through the buffer (where I stored the line), and put them in that format.
How would I do this?
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
-
4
-
4
8 Comments
Hi jewee,
char dd[3], mm[3], yy[3] ;
scanf ("%2s%2s%2s", yy, dd, mm) ;
printf ("%s/%s/%s", dd, mm, yy) ;
or sscanf() and sprintf() if you want to manipulate strings instead of input output.
S.
char dd[3], mm[3], yy[3] ;
scanf ("%2s%2s%2s", yy, dd, mm) ;
printf ("%s/%s/%s", dd, mm, yy) ;
or sscanf() and sprintf() if you want to manipulate strings instead of input output.
S.
When I read in data to a file, that data is at the end, so I read it into a char buffer array. Should I just set, for example, the first 2 bytes which is 99 into yy...etc??
I don't understad what you really want to do now. Do you have a file containing lines "990102", "010901" etc., or you have some data and inside are these dates? Well, let's pass this and suppose that you have allready read a line that contains your date.
If you have a string containing "990102" in the middle it still depends whether the position is fixed or it is prefixed with a word (possibly "date:") or the position of the date is fixed (like 3rd word from beginning).
but if you know the exact position of the date in the string (lets say 'a') you can:
separate the date copying the substring out: strncpy (szDate, &szLine[a], 6) ;
and sscanf() it
or you can separate it using numbers
int dd, mm, yy ;
scanf ("%2d%2d%2d, &yy, &dd, &mm)
or you can get the numbers by your own:
yy = (szLine[a]-'0')*10 + (szLine[a+1]-'0') ;
dd = (szLine[a+2]-'0')*10 + (szLine[a+3]-'0') ;
mm = (szLine[a+4]-'0')*10 + (szLine[a+5]-'0') ;
there are numerous approaches, you have to decide what to do according to your specific situation (for example if you want to calculate with the date further it would be better to get numbers instead of substrings).
S.
If you have a string containing "990102" in the middle it still depends whether the position is fixed or it is prefixed with a word (possibly "date:") or the position of the date is fixed (like 3rd word from beginning).
but if you know the exact position of the date in the string (lets say 'a') you can:
separate the date copying the substring out: strncpy (szDate, &szLine[a], 6) ;
and sscanf() it
or you can separate it using numbers
int dd, mm, yy ;
scanf ("%2d%2d%2d, &yy, &dd, &mm)
or you can get the numbers by your own:
yy = (szLine[a]-'0')*10 + (szLine[a+1]-'0') ;
dd = (szLine[a+2]-'0')*10 + (szLine[a+3]-'0') ;
mm = (szLine[a+4]-'0')*10 + (szLine[a+5]-'0') ;
there are numerous approaches, you have to decide what to do according to your specific situation (for example if you want to calculate with the date further it would be better to get numbers instead of substrings).
S.
I know exactly where the string is within the line...this is how I extract it...
std::string last_field = line.substr(42);
std::string last_field = line.substr(42);
I'm confused with how I use sscanf to separate it considering the location of the year, month and day needs to be changed to month, year, and day.
so you answered you question perfectly by ourself :)
std:: string yy = last_field.substr(0, 2) ;
std:: string dd = last_field.substr(2, 2) ;
std:: string mm = last_field.substr(4, 2) ;
cout << dd << "/" << mm << '/' << yy ;
S.
std:: string yy = last_field.substr(0, 2) ;
std:: string dd = last_field.substr(2, 2) ;
std:: string mm = last_field.substr(4, 2) ;
cout << dd << "/" << mm << '/' << yy ;
S.
Featured Post
In their most recent webinar, Skyport Systems explores ways to isolate and protect critical databases to keep the core of your company safe from harm.
Question has a verified solution.
If you are experiencing a similar issue, please ask a related question
Introduction
This article is a continuation of the C/C++ Visual Studio Express debugger series. Part 1 provided a quick start guide in using the debugger. Part 2 focused on additional topics in breakpoints. As your assignments become a little more …
The goal of the video will be to teach the user the difference and consequence of passing data by value vs passing data by reference in C++. An example of passing data by value as well as an example of passing data by reference will be be given. Bot…
The viewer will learn additional member functions of the vector class. Specifically, the capacity and swap member functions will be introduced.
Suggested Courses
Course of the Month5 days, 14 hours left to enroll
688 members asked questions and received personalized solutions in the past 7 days.
Join the community of 500,000 technology professionals and ask your questions.