Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
• Status: Solved
• Priority: Medium
• Security: Public
• Views: 214

# Equation Issues III

how would I go about getting these equations to ouput the values to the textfields in the web form as they are calculated?

double dr = Double.Parse(DR.Text);
double dl = Double.Parse(DL.Text);
double dt = Double.Parse(DT.Text);
double sn = Double.Parse(snD.Text);
double d = Double.Parse(d0.Text);
double s = Double.Parse(sT.Text);
double m = Double.Parse(MT.Text);
double dx = Double.Parse(dy.Text);
double ct = Double.Parse(cte.Text);
double sn2 = Double.Parse(snM.Text);
double m1 = Double.Parse(ML.Text);
double m2 = Double.Parse(MT.Text);
double d1 = Double.Parse(dd0.Text);
double drs = Double.Parse(DRST.Text);
double d2 = Double.Parse(dd.Text);
double mrt = Double.Parse(MRST.Text);

snD.Text = double.Parse(snD.Text).ToString();

int z;
z = 1000;
TBox.Text = z.ToString();

//DL.Text = (double.Parse(Wavelength.Text) / double.Parse(TBox.Text)).ToString();
sn = (.0088641 + 1.07057 * (.0001)/(dl * dl) + (1.9893 *.000001)/(dl*4*4) - .00017175*(dl*dl)-(dt) * .000001*1+dt/900*(1.01+0.2)*(dl*dl));
d = (dr*dl)/sn;
s = (m - dt);
dx = d*(1+ct*s);

sn2 = (Double.Parse(".0088641") + 1.07057*(Double.Parse(".0001")/(m1 * m1)) + 1.9893*Math.Pow(Double.Parse(".000001")/m1, 4)- Double.Parse("1.7175E-04")*m1*m1-m * (Double.Parse(".000001")*(1+m/900)*(1.01+0.2*m1*m1)));
m2 = (sn2*d)/m1;
d1 = (drs*dl)/sn;
d2 = d1*(1+ct*s);
mrt = (sn2*d2)/m1;
0
devlins
• 2
1 Solution

Commented:
d = (dr*dl)/sn;
d0.Text = d.Tostring()
0

Commented:
oops ...

sn = (.0088641 + 1.07057 * (.0001)/(dl * dl) + (1.9893 *.000001)/(dl*4*4) - .00017175*(dl*dl)-(dt) * .000001*1+dt/900*(1.01+0.2)*(dl*dl));
sn2.Text = sn.ToString();

etc etc
0

## Featured Post

• 2
Tackle projects and never again get stuck behind a technical roadblock.