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  • Status: Solved
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Error in bitwise OR operation?

I am getting an error for the following code...

 #include<stdio.h>
#include<stdlib.h>
#include <string.h>

#define hex 0x00020000;
void main()
{
      unsigned r;
       r=hex | 100;
      printf("%u",r);
      getchar();
}

error C2143: syntax error : missing ';' before '|'

What is the problem?

0
gopikrish
Asked:
gopikrish
  • 2
1 Solution
 
Jaime OlivaresSoftware ArchitectCommented:
Hi gopikrish,
> #define hex 0x00020000;
the last comma is not valid. Would be:
#define hex 0x00020000

Good luck,
Jaime.
0
 
Jaime OlivaresSoftware ArchitectCommented:
To be clearer: #defines don't need an ending colon (;) like regular C code lines.
0
 
ddunleaCommented:
Whilst it's not causing the problem you're seeing, are you sure you want to be ORing decimal 100 i.e. 0x64? You probably want to write 0x100, which will give you a single bit set high,  as opposed to just plain 100 which will give 01100100b
0
 
MysidiaCommented:
Since you have
 #define hex 0x00020000;

The line:
       r=hex | 100;

is actually expanding to
        r=0x00020000; | 100;

Which is not what you want: "| 100;"  is not a valid C statement
Removing the trailing semicolon in the #define hex   line should remedy this
0

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