drakkarnoir
asked on
PHP 5 Constructors
Why is it that I cannot pass a variable to a constructor in PHP 5?
Example:
class Test {
function __construct($constructvar)
{
echo $constructvar;
}
}
$Test = new Test("hi");
if(class_exists($Test))
echo "Test has been initialized.";
else
echo "No go.";
Any ideas? Or have I forgot to remember something about constructors...
Example:
class Test {
function __construct($constructvar)
{
echo $constructvar;
}
}
$Test = new Test("hi");
if(class_exists($Test))
echo "Test has been initialized.";
else
echo "No go.";
Any ideas? Or have I forgot to remember something about constructors...
The only way you can feed it as a variable is by assigning the string name of the class like this
class Test {
function __construct($constructvar)
echo $constructvar;
}
}
$Test = Test;
echo (class_exists($Test)) ? "Test has been initialized." : "No go.";
class Test {
function __construct($constructvar)
echo $constructvar;
}
}
$Test = Test;
echo (class_exists($Test)) ? "Test has been initialized." : "No go.";
a constructor is executed when you create an instance, so there cannot be the possibility of passing a variable. if you need to, you'll have to stick to calling a selfmade constructor method.
...or set the initial value for your variable in your properties declaration. but this abiously lacks the flexibility you are probably looking for.
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i dont see an awful lot of difference between the accepted answer and mine :S
anyone care to shed some light...
anyone care to shed some light...
I addressed the fact that the question was actually Why is it that I cannot pass a variable to a constructor in PHP 5? vs. Why isn't class_exists working. I think points could have been split.
dtan
dtan
I had thought i had highlighted the reason why it wasnt working in my first and second post
>> class_exists is looking for a string name not an initialized class
and
>> The only way you can feed it as a variable is by assigning the string name of the class like this...
oh well :(
>> class_exists is looking for a string name not an initialized class
and
>> The only way you can feed it as a variable is by assigning the string name of the class like this...
oh well :(
I think he was more interested in why
function __construct($constructvar)
}
wasn't working. . . but mistakenly used class_exists .
dtan
function __construct($constructvar)
}
wasn't working. . . but mistakenly used class_exists .
dtan
<?php
class Test {
function __construct($constructvar)
echo $constructvar;
}
}
$Test = new Test;
$Test -> __construct("hi");
echo (class_exists('test')) ? "Test has been initialized." : "No go.";
?>