We value your feedback.
Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!
COURSE of the MONTH
13 days, 11 hours left to enrollBecome a Premium Member and unlock a new, free course in leading technologies each month.
Solved
Find the physical path of file
Posted on 2004-08-04
Hi
I've played around with code like this:
<?php
$conn_id = ftp_connect("xxx.com");
$login_result = ftp_login($conn_id, "user", "passw");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$contents = ftp_nlist($conn_id, ".");
echo implode($contents,"/");
ftp_quit($conn_id);
?>
This code shows the files in a ftp-directory but I would also like to show the physical path to the individual files. Is this possible? Points to those who integrate the necessary code in the above.
Thanx,
Soren
I've played around with code like this:
<?php
$conn_id = ftp_connect("xxx.com");
$login_result = ftp_login($conn_id, "user", "passw");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$contents = ftp_nlist($conn_id, ".");
echo implode($contents,"/");
ftp_quit($conn_id);
?>
This code shows the files in a ftp-directory but I would also like to show the physical path to the individual files. Is this possible? Points to those who integrate the necessary code in the above.
Thanx,
Soren
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
-
5
-
3
2
10 Comments
I don't understand exactly what you want but I guess it is something like this (sorry, I can't test the script right now)
<?php
$conn_id = ftp_connect("xxx.com");
$login_result = ftp_login($conn_id, "user", "passw");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$currentdir = ftp_pwd();
$contents = ftp_nlist($conn_id, ".");
$all = implode($contents,":");
$all = str_replace(":",":$current
echo ($all);
ftp_quit($conn_id);
?>
<?php
$conn_id = ftp_connect("xxx.com");
$login_result = ftp_login($conn_id, "user", "passw");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$currentdir = ftp_pwd();
$contents = ftp_nlist($conn_id, ".");
$all = implode($contents,":");
$all = str_replace(":",":$current
echo ($all);
ftp_quit($conn_id);
?>
I think this only returns the directory name. I would like it to return the physical path to the individual files. Like the asp-function Server.MapPath.
If the ftp user is set up to log in to the root directory on the server then the ftp_pwd() will return the entire phsyical directory of the file and Jaime's code should work.
I've probably used the wrong terms, but by physical path I mean for example "d:\inetpub\wwwroot\index.
Correct if your ftp user starts in wwwroot, ftp_pwd() will not return the whole path, but if you set the ftp login to start in d:\ it will return the whole path.
Ok - so if I start in wwwroot is there a way to get the whole physical path anyway (the whole d:\inetpub\wwwroot)?
If not, I guess I would have to upload a asp-script to the server (this only targets iis-servers) and then afterwards read the script and see what it returns.
If not, I guess I would have to upload a asp-script to the server (this only targets iis-servers) and then afterwards read the script and see what it returns.
If the php command ftp_raw is working on the server you could try something like
ftp_raw ($conn_id,'pwd')
But I have not tested this because the function does not work with my version of php.
http://us2.php.net/manual/en/function.ftp-raw.php
ftp_raw ($conn_id,'pwd')
But I have not tested this because the function does not work with my version of php.
http://us2.php.net/manual/en/function.ftp-raw.php
This piece of code return the correct top folder list og files and folders for both linux- and windows server. I don't know if this can help:
<?php
$conn_id = ftp_connect("ftp.xxx.com");
$login_result = ftp_login($conn_id, "yyy", "zzz");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$contents = ftp_nlist($conn_id, ".");
echo implode($contents,"/");
ftp_quit($conn_id);
?>
<?php
$conn_id = ftp_connect("ftp.xxx.com");
$login_result = ftp_login($conn_id, "yyy", "zzz");
if ((!$conn_id) || (!$login_result)) {
echo "Ftp connection has failed!";
die;
} else {
echo "Connected";
}
$contents = ftp_nlist($conn_id, ".");
echo implode($contents,"/");
ftp_quit($conn_id);
?>
Featured Post
Ready to improve network connectivity? Watch this webinar to learn how SD-WANs and a one-click instant connect tool can boost provisions, deployment, and management of your cloud connection.
Question has a verified solution.
If you are experiencing a similar issue, please ask a related question
Foreword (July, 2015)
Since I first wrote this article, years ago, a great many more people have begun using the internet. They are coming online from every part of the globe, learning, reading, shopping and spending money at an ever-increasing ra…
This article discusses how to implement server side field validation and display customized error messages to the client.
The viewer will learn how to count occurrences of each item in an array.
The viewer will learn how to look for a specific file type in a local or remote server directory using PHP.
Suggested Courses
Course of the Month13 days, 11 hours left to enroll
801 members asked questions and received personalized solutions in the past 7 days.
Join the community of 500,000 technology professionals and ask your questions.