settin focus using tabindex

i'm tryin to set focus in the next text box
by pressing vbKeyDown in the text box

there are three n boxes txt_1 , txt_2 and txt_3 ... txt_n

when i press down key in txt_1 focus should be set to txt_2
and from txt_2 to txt_3
and upto txt_n

i will call a function in each textboxes keydown event
which will shift the focus to the next text box

function :
private function shiftFocus(byval index as integer)
    dim i as integer
    me.controls(i).setfocus ' this line is setting wrong focus
end function

call :

call (txt_1.tabIndex)

any solution to my problem is worth 500 points.

Who is Participating?
GrahamSkanConnect With a Mentor RetiredCommented:
ryancys' comment is the pragmatic answer.

However,  to understand why your attempt did not work, you should understand that TabIndex is not the same as the index in the controls collection. Therefore you cannot address a control by its TabIndex. You would have to find it programatically:

Option Explicit

Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer)
KeyCode = 9
    NextBox Text1
End Sub

Private Sub Text2_KeyDown(KeyCode As Integer, Shift As Integer)
    NextBox Text2
End Sub

Private Sub Text3_KeyDown(KeyCode As Integer, Shift As Integer)
    NextBox Text3
End Sub

Sub NextBox(TextX As Control)
    Dim ctl As Object
    Dim i As Integer
    Dim m As Integer
    Dim Minctl As Control
    m = TextX.TabIndex
    Set Minctl = Me.Text1
    For Each ctl In Me.Controls
        If TypeOf ctl Is TextBox Then
            If ctl.TabIndex = TextX.TabIndex + 1 Then
                Exit Sub
            End If
            If ctl.TabIndex < m Then
                m = ctl.TabIndex
                Set Minctl = ctl
            End If
        End If
    Next ctl
    Minctl.SetFocus 'last box reached, back to start
End Sub
Ryan ChongCommented:
Try use sendkeys function, like:

Private Sub txt_1_KeyDown(KeyCode As Integer, Shift As Integer)
    If KeyCode = vbKeyReturn Then SendKeys "{Tab}"
End Sub

in the case that the TabIndex(s) are in order

amit_mi2Author Commented:
nice answer Graham
same thing i worked out
after posting
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