Solved

Complicated sql query with 3 one to many tables.

Posted on 2004-08-05
5
830 Views
Last Modified: 2008-01-09
Hola.

I have 3 tables.

1.  Parent.
    PID
    PNAME

2.  Child.
     CID
     PID_fk
     CNAME

3.  ChildAge
     CAID
     CID_fk
     Age
     Height

What I want is a select query that will return the age of the children in one column and their heights at these ages in the next columns.  So something like:

Age    Martin   Steve   Johan
1        0.4       0.5       0.6
2        0.6       0.7       0.7
3        1.0       1.2       1.15

So I dont mind building a query for each parent and I need to be able to handle upto 9 children so I dont need an exponentially complicated query.

HELP!

Asim

0
Comment
Question by:asiminator
  • 2
  • 2
5 Comments
 
LVL 23

Accepted Solution

by:
seazodiac earned 250 total points
ID: 11727000
let's say 9 is the upper limit (in my example, the name are arbitary)

select age, max(decode(upper(name), 'MARTIN', height, 0)) "Martin",
max(decode(upper(name), 'STEVE', height, 0)) "Steve",
max(decode(upper(name), 'JOHAN', height, 0)) "Johan",
max(decode(upper(name), 'SMITH', height, 0)) "Smith",
max(decode(upper(name), 'JACK', height, 0)) "Jack",
max(decode(upper(name), 'MIKE', height, 0)) "Mike",
max(decode(upper(name), 'RICHARD', height, 0)) "Richard",
max(decode(upper(name), 'TERESA', height, 0)) "Teresa",
max(decode(upper(name), 'BONNIE', height, 0)) "Bonnie"
from (select A.cid, A.name, B.age, B.height
from child A, childage B
where A.cid = B.cid_fk
and upper(A.name) in ('MARTIN', 'STEVE', 'JOHAN', 'SMITH', 'JACK', 'MIKE', 'RICHARD', 'TERESA', 'BONNIE'));

0
 
LVL 8

Expert Comment

by:sapnam
ID: 11727118
Are you going to use SQL or some tool like Report Builder finally to display this output.
0
 

Author Comment

by:asiminator
ID: 11727341
thanks for the rapid response.

I still have a problem.... when I run the query it says age is not a single-group group function.

Any ideas?

Asim
0
 
LVL 23

Expert Comment

by:seazodiac
ID: 11727358
yes, that's a syntax error, i fixed in the query below:

select age, max(decode(upper(name), 'MARTIN', height, 0)) "Martin",
max(decode(upper(name), 'STEVE', height, 0)) "Steve",
max(decode(upper(name), 'JOHAN', height, 0)) "Johan",
max(decode(upper(name), 'SMITH', height, 0)) "Smith",
max(decode(upper(name), 'JACK', height, 0)) "Jack",
max(decode(upper(name), 'MIKE', height, 0)) "Mike",
max(decode(upper(name), 'RICHARD', height, 0)) "Richard",
max(decode(upper(name), 'TERESA', height, 0)) "Teresa",
max(decode(upper(name), 'BONNIE', height, 0)) "Bonnie"
from (select A.cid, A.name, B.age, B.height
from child A, childage B
where A.cid = B.cid_fk
and upper(A.name) in ('MARTIN', 'STEVE', 'JOHAN', 'SMITH', 'JACK', 'MIKE', 'RICHARD', 'TERESA', 'BONNIE'))
group by age;
0
 

Author Comment

by:asiminator
ID: 11727445
cool.... thanks.

Youre a champ!
0

Featured Post

Live: Real-Time Solutions, Start Here

Receive instant 1:1 support from technology experts, using our real-time conversation and whiteboard interface. Your first 5 minutes are always free.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Article by: Swadhin
From the Oracle SQL Reference (http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/queries006.htm) we are told that a join is a query that combines rows from two or more tables, views, or materialized views. This article provides a glimps…
From implementing a password expiration date, to datatype conversions and file export options, these are some useful settings I've found in Jasper Server.
This video shows information on the Oracle Data Dictionary, starting with the Oracle documentation, explaining the different types of Data Dictionary views available by group and permissions as well as giving examples on how to retrieve data from th…
This video shows how to Export data from an Oracle database using the Datapump Export Utility.  The corresponding Datapump Import utility is also discussed and demonstrated.

813 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

14 Experts available now in Live!

Get 1:1 Help Now