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Convert seconds to a date in oracle plsql

Posted on 2004-08-05
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Last Modified: 2012-06-22
I have a database feild that is stored in seconds from epoch. Is there a simple way to convert this date to a date or timestamp datatype.
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Question by:CodeMachine
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6 Comments
 
LVL 15

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jdlambert1 earned 64 total points
ID: 11731829
I don't know of a simple way. Unless someone knows of a PL/SQL function for this, I'd create a stored procedure. Use variables and basic math to turn the seconds into years, months, days, hours, & seconds, then add those to the epoch and output the result.

(Next time you have a PL/SQL question, you'll probably get more responses by posting in the Oracle group instead of the generic database group.)
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LVL 10

Assisted Solution

by:winzig
winzig earned 62 total points
ID: 11732152
Probably folloving formula may help
F_StartTime / (24 * 60 * 60) + 25569)

This code converts ORacle date( no of second from 1.1.1970) to microsoft date (days from 1.1.1900) and then you can use Buid In OS function which convert this no to DATE. (just retype this number to date)
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LVL 15

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by:ishando
ishando earned 62 total points
ID: 11732534
If EPOCH is a date constant containing the start date of the epoch, e.g 1970-01-01 00:00:00, and utime is a variable containing the number of seconds from the epoch, then the date can be calculated using:

  select to_date(to_char(EPOCH, 'j') + floor(utime/86400), 'j')    /* gets date part of date */
           + (utime/86400 - floor(utime/86400))                          /* the time part */
  from dual;

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LVL 4

Assisted Solution

by:ramumorla
ramumorla earned 62 total points
ID: 11736826
select
        Days,
        A,
        TRUNC(A*24)                                     Hours,
        TRUNC(A*24*60 - 60*TRUNC(A*24))                 Minutes,
        TRUNC(A*24*60*60 - 60*TRUNC(A*24*60))           Seconds,
        TRUNC(A*24*60*60*100 - 100*TRUNC(A*24*60*60))   mSeconds
from
(
select
        trunc(&DIF)             Days,

        &Dif - trunc(&DIF)      A
from dual
)
;
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