Solved

Zipping files up in Servlet

Posted on 2004-08-06
13
264 Views
Last Modified: 2008-02-20
I have a problem with a servlet that I'm using to zip up alot of files into one file... but I don't think I have the path correct... I'm not sure what to do since I've tried so many combinations, hoping to find the right path...

here's my code:      filesToZip[] is an array containing filenames for the files to be zipped... and zipFileName is the name of the zip file (ie. asdf.zip)

try {
     ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(zipFileName));
                                    
     // Set the compression ratio
     zos.setLevel(Deflater.DEFAULT_COMPRESSION);
                                    
    // iterate through the array of files, adding each to the zip file
     for (int i = 0; i < filesToZip.length; i++) {
            location = "/protected/files/" + filesToZip[i];
                                                                        
            // Associate a file input stream for the current file
            FileInputStream in = new FileInputStream(location); //***************
      
            // Add ZIP entry to output stream.
            zos.putNextEntry(new ZipEntry(location));
      
            int len;
                                    
            while ((len = in.read(buffer)) > 0) {
                  zos.write(buffer, 0, len);
            }
      
      
            // Close the current entry
            zos.closeEntry();
      
            // Close the current file input stream
            in.close();
      }
                              
      // Close the ZipOutPutStream
      zos.close();

} catch(Exception e) {
     System.out.println("Exception: " + e.getMessage());
}


My files are located /user/jakarta-tomcat/webapps/ROOT/protected/files/

Currently, at the place where i have labelled with alot of asterisks (//***************), an exception is thrown... so i have a feeling that they cannot find these files

Can anyone offer any suggestions?  thanks!

i usually like to offer more points, but today i only have 90...=\
0
Comment
Question by:alskdj80
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 8
  • 5
13 Comments
 
LVL 35

Accepted Solution

by:
TimYates earned 90 total points
ID: 11737438
Have you tried:

 location = System.getProperty( "tomcat.home" ) + "/webapps/ROOT/protected/files/" + filesToZip[i];
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737495
I just tried it but I get a null value for System.getProperty( "tomcat.home" )
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737503
oh, but i just tried System.getProperty( "catalina.home" ) and it worked... i'll let you know what happens
0
[Live Webinar] The Cloud Skills Gap

As Cloud technologies come of age, business leaders grapple with the impact it has on their team's skills and the gap associated with the use of a cloud platform.

Join experts from 451 Research and Concerto Cloud Services on July 27th where we will examine fact and fiction.

 
LVL 3

Author Comment

by:alskdj80
ID: 11737568
no, it still doesnt seem to find it...

basically what im doing to check is this:

location = System.getProperty("catalina.home") + "/webapps/ROOT/protected/files/" + filesToZip[i];
System.out.println("here");  //CHECK1
FileInputStream in = new FileInputStream(location); //***************
System.out.println("works");  //CHECK2

it always prints "here" but never prints "works", so i assume that location is never found...
0
 
LVL 35

Expert Comment

by:TimYates
ID: 11737599
Try:

System.out.println("here (" + location + ")" );  //CHECK1

does it print out a reasonable location?
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737622
yes, it does... it prints out:
/home/user/jakarta-tomcat/webapps/ROOT/protected/files/asdf.txt
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737634
(that is one of the filenames in the filesToZip array)
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737648
i have access to unix shell as well, so i went to the root directory and typed:
>> cd /home/user/jakarta-tomcat/webapps/ROOT/protected/files

and i got to the right directory...
0
 
LVL 35

Expert Comment

by:TimYates
ID: 11737709
What exception is it printing out?

catch(Exception e) {
     System.out.println("Exception: " + e.getMessage());
     e.printStackTrace() ;
}
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737793
im not sure... im not actually getting errors from the catches... but i set the error prints so i know when it gets the exception...

i just tried putting one file through the zip... a file that i placed into /user/jakarta-tomcat/asdf.txt

i put this in the code:
filesToZip = new String[1];
filesToZip[0] = "asdf.txt";

and it worked!


but when i try doing this (and also putting asdf.txt into the appropriate folder), it produces the same error again:
filesToZip[0] = "/webapps/ROOT/asdf.txt";
0
 
LVL 35

Expert Comment

by:TimYates
ID: 11737822
what user is tomcat running as?  Does it have read access for that folder?  Does it have write access where it's trying to write the file?
0
 
LVL 3

Author Comment

by:alskdj80
ID: 11737905
hmm, i think i understand why... i had been taking the filenames from database, but apparently there was some corruption in some of the filenames...

thanks alot for helping me!  i think i can take it from here
0
 
LVL 35

Expert Comment

by:TimYates
ID: 11738016
No worries ;-)  Glad I could give you things to do whilst you worked it out ;-)

Good luck with it :-)

Tim
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

There are times when I have encountered the need to decompress a response from a PHP request. This is how it's done, but you must have control of the request and you can set the Accept-Encoding header.
First of all let me say that the only language that I speak is English, but in answering questions here I often come across people whose English skills are not the best and I’d like to be able to communicate better with them, and the following descr…
In this video, viewers will be given step by step instructions on adjusting mouse, pointer and cursor visibility in Microsoft Windows 10. The video seeks to educate those who are struggling with the new Windows 10 Graphical User Interface. Change Cu…
In this brief tutorial Pawel from AdRem Software explains how you can quickly find out which services are running on your network, or what are the IP addresses of servers responsible for each service. Software used is freeware NetCrunch Tools (https…
Suggested Courses

615 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question