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BlackCollarWorker

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How do I get the record ID of the record I just inserted? Using C# ASP.NET SQL Server 2000

Hi,

In MSSQL I have auto incrementing PK for the row I'm inserting into. The the code I use below is to insert into the table. What I need is as soon as I insert the record, I also need to return back what the PK was of my newly inserted row. I will need to use this value for another section of the FORM for use as a FK into another table in which I going insert some other data based on a few criterias. I tried to us @@IDENTITY to no avail. Any help is greatly appreciated. I pretty new at this stuff and just learning. Thank You.

void InsertCommand(Object sender, System.EventArgs e) {
            SqlConnection myConnection;
            myConnection = new SqlConnection("Server=NAME;uid=USERNAME;pwd=PASSWORD;database=DBNAME;");
            SqlCommand myCommand;
            myCommand = new SqlCommand("Insert Into fundAcctTBL (orgName, taxID, address01, address02, city, state, zip, phone, webURL, fax, contactName, dayPhone, evePhone, email, typeOrgID, typeOrgOther, org501C, listOrg, promoKit, addToWeb) Values (@orgName, @taxID, @address01, @address02, @city, @state, @zip, @phone, @webURL, @fax, @contactName, @dayPhone, @evePhone, @email, @typeOrgID, @typeOrgOther, @org501C, @listOrg, @promoKit, @addToWeb)", myConnection);
            myCommand.Parameters.Add("@orgName", SqlDbType.VarChar, 255).Value = txtbxOrgName.Text;
            myCommand.Parameters.Add("@taxID", SqlDbType.VarChar, 50).Value = txtbxTaxID.Text;
            myCommand.Parameters.Add("@address01", SqlDbType.VarChar, 500).Value = txtbxAddress.Text;
            myCommand.Parameters.Add("@address02", SqlDbType.VarChar, 500).Value = txtbxAddress02.Text;
            myCommand.Parameters.Add("@city", SqlDbType.VarChar, 255).Value = txtbxCity.Text;
            myCommand.Parameters.Add("@state", SqlDbType.VarChar, 255).Value = txtbxState.Text;
            myCommand.Parameters.Add("@zip", SqlDbType.VarChar, 15).Value = txtbxZip.Text;
            myCommand.Parameters.Add("@phone", SqlDbType.VarChar, 15).Value = txtbxPhoneAreaCode.Text + txtbxPhone.Text;
            myCommand.Parameters.Add("@webURL", SqlDbType.VarChar, 255).Value = txtbxWebURL.Text;
            myCommand.Parameters.Add("@fax", SqlDbType.VarChar, 15).Value = txtbxFaxAreaCode.Text + txtbxFax.Text;
            myCommand.Parameters.Add("@contactName", SqlDbType.VarChar, 255).Value = txtbxContactName.Text;
            myCommand.Parameters.Add("@dayPhone", SqlDbType.VarChar, 15).Value = txtbxDayPhoneAreaCode.Text + txtbxDayPhone.Text;
            myCommand.Parameters.Add("@evePhone", SqlDbType.VarChar, 15).Value = txtbxEvePhoneAreaCode.Text + txtbxEvePhone.Text;
            myCommand.Parameters.Add("@email", SqlDbType.VarChar, 255).Value = txtbxEmail.Text;
            myCommand.Parameters.Add("@typeOrgID", SqlDbType.Int, 4).Value = radbtnDescOrg.SelectedItem.Value;
            myCommand.Parameters.Add("@typeOrgOther", SqlDbType.VarChar, 255).Value = txtDescOrgOther.Text;
            myCommand.Parameters.Add("@org501C", SqlDbType.Int, 4).Value = radbtn501Org.SelectedItem.Value;
            myCommand.Parameters.Add("@listOrg", SqlDbType.Int, 4).Value = radbtnListing.SelectedItem.Value;
            myCommand.Parameters.Add("@promoKit", SqlDbType.Int, 4).Value = radbtnFundKit.SelectedItem.Value;
            myCommand.Parameters.Add("@addToWeb", SqlDbType.Int, 4).Value = radbtnAddWeb.SelectedItem.Value;
            myConnection.Open();
            myCommand.ExecuteNonQuery();
            myConnection.Close();
            Response.Redirect("../");
            }
Avatar of Timbo87
Timbo87

You can add a return to the stored procedure and return @@identity.

In the stored procedure:

Insert ... into ...
return @@identity

And in the code:
myCommand.Parameters.Add("@return", SqlDbType.Int, 4).Direction = ParameterDirection.ReturnValue;
Avatar of BlackCollarWorker

ASKER

I'm actually not using a stored procedure, I'm just inserting this directly to the database, is using a stored procedure the only way of doing this? Thanks.

Michael
ASKER CERTIFIED SOLUTION
Avatar of gregoryyoung
gregoryyoung
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