Solved

EXCEL VBA Question

Posted on 2004-08-09
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632 Views
Last Modified: 2012-05-05
Dear Experts,

In Excel97, I want a Calendar to pop-up when the user clicks on a cell in specific cell ranges. The user should only be able to enter dates chosen from the Calendar into the cell.

At the moment, I am using the following code. Form1 has the Calendar control on it. What this code does is that when an Active Cell is within the specified range, then when the user presses a shortcut, it runs the macro to pop-up the Calendar. This works fine, but I'd like the Calendar to pop-up when the user simply highlights a cell (makes a cell Active) in the specified ranges.

Thanks,
DocNash


Sub auto_open()
Dim KeyCells As String
KeyCells = "D3:D1000, E3:E1000, H3:H1000, J3:J1000, K3:K1000"
If Not Application.Intersect(ActiveCell, Range(KeyCells)) Is Nothing Then DoIt
End Sub

Sub DoIt()
UserForm1.Show
End Sub
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Question by:DoctorNash
  • 3
4 Comments
 
LVL 35

Accepted Solution

by:
[ fanpages ] earned 75 total points
ID: 11751012
Hi,

You need to place your code presently in auto_open() in the Worksheet_SelectionChange() event.

Replacing "ActiveCell" with "Target", thus:

Private Sub Worksheet_SelectionChange(ByVal Target As Range)

Dim KeyCells As String
KeyCells = "D3:D1000, E3:E1000, H3:H1000, J3:J1000, K3:K1000"
If Not Application.Intersect(Target, Range(KeyCells)) Is Nothing Then DoIt

End Sub


BFN,

fp.
0
 
LVL 35

Expert Comment

by:[ fanpages ]
ID: 11751016
PS. This area is probably the most appropriate for your question:

http://www.experts-exchange.com/Applications/MS_Office/Excel/
0
 

Author Comment

by:DoctorNash
ID: 11760469
Nice piece of work - thanks FanPages. By the way, it still seemed to work with 'ActiveCell' in the expression instead of 'Target'.
Regards,
DocNash
0
 
LVL 35

Expert Comment

by:[ fanpages ]
ID: 11762238
Hi,

Yes, ActiveCell would work if you had just selected a single cell, but if you had multiple cells selected, then Target would be the most appropriate.

Either way, glad you're happy with the solution.

BFN,

fp.
[ http://NigelLee.info ]
0

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