• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 610
  • Last Modified:

OpenDir: Invalid argument

I'm trying to get working following code:

$path = "C:\\@\\";
$dp = opendir($path);

and get following error:

OpenDir: Invalid argument (errno 22)

Any chance to make it working with '@' character in path?

TIA,
dumb
0
iam_dumb
Asked:
iam_dumb
1 Solution
 
thecode101Commented:
Try this:
$dp = opendir('c:/@');

I tested it using the following script and it worked correctly:
<?php
if ($handle = opendir('c:/@'))
{
      while (false !== ($file = readdir($handle)))
         {
              if ($file != "." && $file != "..")
                  {
                        echo $file;
              }
       }
}
else
      echo "Unable to Open Folder";
?>
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now