• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 3424
  • Last Modified:

How to determine palindrome using stack and queue?

I hv do my works, but i have a problem between it. CAn somebody help me to solve it...

#include <stdio.h>
#include <string.h>
#define SIZE 100

typedef char item_t;

typedef struct {
      item_t Items[SIZE];
      int top;
}Stack_t;

typedef struct{
      int count,front, rear;
      item_t Item[SIZE];
}Queue_t;

void InitialiseStack (Stack_t *S)
{      S->top=0;      }

int emptystack (Stack_t S)
{      return (S.top==0);      }

int fullstack (Stack_t S)
{      return (S.top==SIZE);      }


void push (char x,Stack_t *S)
{
      if(fullstack(*S))
            printf("stack overflow\n");
      else{
                  S->Items[S->top]=x;
                  ++(S->top);
      }
}

void pop (Stack_t *S, char *x)
{
      if(emptystack(*S))
            printf("stack empty\n");
      else{
            --(S->top);
            *x=S->Items[S->top];
      }
}

void InitialiseQueue (Queue_t *Q)
{
      Q->count=0;
      Q->front=0;
      Q->rear=-1;
}

int emptyq (Queue_t Q)
{      return (Q.count==0);      }

int fullq (Queue_t Q)
{      return (Q.count==SIZE);      }

void insert(item_t y, Queue_t *Q)
{
      if (fullq(*Q))
            printf("queue overflow\n");
      else{
            Q->rear=(Q->rear+1)%SIZE;
            Q->Item[Q->rear]=y;
            Q->count++;
      }
}

void Remove (Queue_t *Q, item_t *y)
{
      if(emptyq(*Q))
            printf("queue empty\n");
      else{
            *y=Q->Item[Q->front];
            Q->front=(Q->front+1)%SIZE;
            --(Q->count);
      }
}

main ()
{
      Stack_t S;
      Queue_t Q;
      item_t input[SIZE],Q_output[SIZE]="",S_output[SIZE]="";
      int i,length;

      InitialiseStack(&S);
      InitialiseQueue(&Q);

      printf("Enter a words to reverse> ");
      for(i=0,input[i]=getchar();input[i]!='\n';i++,input[i]=getchar())
      {
            insert(input[i],&Q);
            push(input[i],&S);
      }

      length=strlen(input);

      for(i=0;i<length;i++)
      {
            while(!emptystack(S)){
                  Remove(&Q,&Q_output[i]);
                  pop(&S,&S_output[i]);
            }
      
            if(Q_output[i]!=S_output[i])
            {
                  printf("\nThe words are not palindrome\n");
                  return 0;
            }

            else if(Q_output[i]==S_output[i])
                  printf("\n%s",S_output[i]);
      }
      
      putchar('\n');

      return 0;
}
0
lawrence_psk
Asked:
lawrence_psk
1 Solution
 
Jase-CoderCommented:
well when you pop stuff off the stack you are getting the data in reverse order so once you have popped the data off check to see if it still spells the same word. If it does then it is a palindrome
0
 
jandhbCommented:
can you show me what you changed to get this working?
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Cloud Class® Course: Microsoft Office 2010

This course will introduce you to the interfaces and features of Microsoft Office 2010 Word, Excel, PowerPoint, Outlook, and Access. You will learn about the features that are shared between all products in the Office suite, as well as the new features that are product specific.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now