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Character class. Shorten code for checking upper and lower case.

Posted on 2004-08-15
Medium Priority
289 Views
Can anyone help advice on the following?

Is there any way to shorten the condtion for checking upper and lower case?

Given that the loop accept only 'Y', 'y', 'N' and 'n' for yes and no?

do {
......
......
} while ((toCon!='Y') && (toCon! ='y') && (toCon!='N') && (toCon!= 'n'));

Do any of the these methods come into use for solving the above-mentioned qn?

Character.isLowerCase(chr)
Character.isUpperCase(chr)
Character.toLowerCase(chr)
Character.toUpperCase(chr)
Character.isLetter(chr)

0
Question by:coffee_bean
• 7
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• +1

LVL 86

Accepted Solution

CEHJ earned 800 total points
ID: 11804809
Yes - use toLowerCase

toCon = Character.toLowerCase(toCon);
0

LVL 86

Assisted Solution

CEHJ earned 800 total points
ID: 11804818
do {
//
}while (toCon != 'n' && toCon != 'y');
0

LVL 7

Expert Comment

ID: 11804883
You may also use something like:

public static boolean isYNyn( char ch )
{
ch &= ~32;
return ch == 'Y' || ch == 'N';
}

0

LVL 86

Expert Comment

ID: 11804900
>>You may also use something like ...

Although it's generally not too good to be assumptive about character encodings

0

LVL 7

Expert Comment

ID: 11805118
Your'e right but the coding for y, n, Y, N is same in every encoding (beside EBCDIC perhaps) :-)
0

LVL 86

Expert Comment

ID: 11805127
>>but the coding for y, n, Y, N is same in every encoding

It is *at the moment* yes ... ;-)
0

LVL 92

Assisted Solution

objects earned 400 total points
ID: 11805933
do {
......
......
} while ("YyNn".indexOf(toCon)>=0);

That way you can easily add exctra options.

or

do {
......
......
} while ("YN".indexOf(Character.toUpperCase(toCon))>=0);
0

Author Comment

ID: 11845812

I tested out the codes on simple stt below and it worked if I enter Y or y or N or n to terminate a loop.

But I couldn't get it to work the other way round if it's for continuing a loop using while (toCon == 'n' && toCon == 'y');

-----------------------------------
char toCon;
char option;

do {
System.out.println("End loop? ");
toCon = Character.toLowerCase(option);
}while (toCon != 'n' && toCon != 'y');

0

LVL 86

Expert Comment

ID: 11845911
I liked objects' one the best myself ;-)

>>while (toCon == 'n' && toCon == 'y');

How could both conditions be simultaneously true? ;-)
0

Author Comment

ID: 11846131

I tested out ur codes and it works well if it's for continuing loop.

char toCon;
do {
System.out.println("To loop? ");
}while ("YN".indexOf(Character.toUpperCase(toCon))>=0);

Couldn't get it terminated ("End loop?") if Y or y or N or n  is entered when  condition is changed to !=. Similarly case for 'while ("YyNn".indexOf(toCon)>=0);' .

I assume this code read the first char of letter entered. It will only terminate when Y is entered to a 'while ("YyNn".indexOf(toCon) !=0);'.
0

LVL 86

Expert Comment

ID: 11846212
It seems rather strange that you should wish it to terminate when either 'y' or 'n' is entered. What is the functionality required here?
0

LVL 86

Expert Comment

ID: 11846267
A normal usage pattern would be:

do {
System.out.print("Do you want to stop now? (y\n) ");
} while("Yy".indexOf(toCon) < 0);
0

Author Comment

ID: 11846610
Well, I am new to Java. A beginner learner.

I was given this qn without any stt provided in the do while loop.  I was kind of obscured with trying to shorten the condtion stt while getting it to work (loop). I didn't notice the conflicting condition until much later.  So I treat the lower & upper case Y & N as any other letter to get the stt to loop or otherwise.

Really appreciate all the answers. It has helped me learn something on the Char class method which I won't be able on my own or from my classmates.
0

LVL 92

Expert Comment

ID: 11846679
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