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Very simple bash question

Posted on 2004-08-16
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Last Modified: 2010-04-21
This has to be an easy question, I am currently brain-fried from doing other bash scripting...

I have a file that logs timestamps every 20 minutes...
I an error occurs on the system it is logged in this file...
Example:
2004-08-14 22:38:25: ------ TimeCheck - Sat Aug 14 22:40:00 2004
2004-08-14 22:58:25: ------ TimeCheck - Sat Aug 14 23:00:00 2004
2004-08-14 23:18:24: ------ TimeCheck - Sat Aug 14 23:20:00 2004
2004-08-14 23:25:09: ERROR Message goes here
2004-08-14 23:25:10: Additional error info here
2004-08-14 23:25:12: and here
2004-08-14 23:25:12: and here
2004-08-14 23:25:12: and here

etc.. etc...
I need, in my script to be able to cat this file, find the last TimeCheck, report the last TimeCheck, then print out the next 15 lines or so...

I don't mind using awk or sed or anything!!! Just has to be in a bash script...
I could work on this for another hour or so, but I need some sleep..

Thanks in advance.
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Question by:g8ballz0fyre
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4 Comments
 
LVL 11

Expert Comment

by:cjjclifford
ID: 11808191

#!/bin/bash

# error checking needs completion!
filename=$1

awk '/TimeCheck/{i=0;trc=1}{ if( trc == 1 && i != 16 ){ last_15[i++] = $0}}}END{for( j = 0; j != i; j++){ print last_15[j]}}' $filename
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Accepted Solution

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sunnycoder earned 200 total points
ID: 11808194
Hi g8ballz0fyre,

tac logfile |  grep "time stamp"  -B 15 -m 1

Sunnycoder
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LVL 11

Expert Comment

by:cjjclifford
ID: 11808196
Sorry, too many brackets in the awk program - here's the correct one...

awk '/TimeCheck/{i=0;trc=1}{ if( trc == 1 && i != 16 ){ last_15[i++] = $0}}END{for( j = 0; j != i; j++){ print last_15[j]}}'
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LVL 11

Expert Comment

by:lbertacco
ID: 11808263
Sunnycoder, I'd pipe the output to tac again to get lines the original order:

tac logfile |  grep "TimeCheck"  -B 15 -m 1 | tac
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