[Okta Webinar] Learn how to a build a cloud-first strategyRegister Now

x
?
Solved

string output

Posted on 2004-08-16
13
Medium Priority
?
232 Views
Last Modified: 2010-03-31
quick quesiton. i am playing around with Strings and different methods. i am taking a users keyboard input and displaying the output using different built in functions and i also coded a class that reverses the output. what i am trying to do now is insert somethign like println() to make my output display down??? can anyone suggest where i should put that???

input: hello
output:
h
e
l
l
o
[code]
//in main
  System.out.println("Please input a string ex. WELCOME");
   KBI.pause();
   String result = KBI.getstring();
   System.out.println("output of input as is "+result);
   System.out.println("length of input "+result.length());
   System.out.println("output of input as uppercase "+result.toUpperCase());
   System.out.println("output of input as lowercase "+result.toLowerCase());
   System.out.println("topDown() output "+output.topDown(result));
   System.out.println();

//class
class output
{
   static public String topDown(String s)
      {
        StringBuffer result = new StringBuffer();
        for(int k = s.length()-1; k >=0; k--)
        {
          result.append(s.charAt(k));
        }//end for
        return result.toString();
      }//end topDown
}//end output class

[/code]
0
Comment
Question by:annie613
  • 8
  • 5
13 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810311
You just need to do

System.out.println(topDown(result));
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810323
You can also do

System.out.println(new StringBuffer(result).reverse());
0
 

Author Comment

by:annie613
ID: 11810372
i have that in my code

System.out.println(topDown(result));//your suggestion
System.out.println("topDown() output "+output.topDown(result));//my code

and it prints output as
input: hello
output: olleh

but how do i get it to print

o
l
l
e
h

im missing how to use System.out.print to display myoutput top-down???
0
Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

 
LVL 86

Accepted Solution

by:
CEHJ earned 200 total points
ID: 11810411
Oh you just need to print each character.

char[] chars = reversed.toCharArray();
for(int i = 0;i < chars.length;i++) {
      System.out.println(chars[i]);
}
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810421
i.e.

String reversed = topDown(result));

// Now the code i posted
0
 

Author Comment

by:annie613
ID: 11810437
do i put that in my output class or will that array just be in the main class
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810452
May as well keep it in the main class
0
 

Author Comment

by:annie613
ID: 11810537
i seem to be getting an error on compile
that it is expecting another ;

String reversed = topDown(result));//ERROR ON THIS LINE
   char[] chars = reversed.toCharArray();
   for(int i = 0 ; i < chars.length; i++)
   {
     System.out.println(chars[i]);
   }

   System.out.println("Please input a string ex. WELCOME");
   KBI.pause();
   String result = KBI.getstring();
   System.out.println("output of input as is "+result);
   System.out.println("length of input "+result.length());
   System.out.println("output of input as uppercase "+result.toUpperCase());
   System.out.println("output of input as lowercase "+result.toLowerCase());
   System.out.println("topDown() output "+output.topDown(result));
   System.out.println("different approach for display of input "+new StringBuffer(result).reverse());
}
class output
{
   static public String topDown(String s)
      {
        StringBuffer result = new StringBuffer();
        for(int k = s.length() - 1; k >= 0; k--)
        {
          result.append(s.charAt(k));
        }//end for  
        return result.toString();
      }//end topDown
}//end output class
0
 

Author Comment

by:annie613
ID: 11810588
nevermind...i just put the code in the wrong place..
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810591
That's because you're doing things in the wrong order. The new code should be placed *after* you've got the value of 'result', not before
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810719
:-)
0
 

Author Comment

by:annie613
ID: 11810748
thanks for the help and insight :)
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 11810763
No problem ;-)
0

Featured Post

VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
Introduction This article is the first of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article explains our test automation goals. Then rationale is given for the tools we use to a…
The viewer will learn how to implement Singleton Design Pattern in Java.
This tutorial will introduce the viewer to VisualVM for the Java platform application. This video explains an example program and covers the Overview, Monitor, and Heap Dump tabs.
Suggested Courses
Course of the Month19 days, 10 hours left to enroll

873 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question