Solved

Remoting

Posted on 2004-08-18
6
243 Views
Last Modified: 2008-02-01
Ola,

I have this book on .NET networking and it has an example of remoting.

In the example I created a client ( winForm ), a remotingObject ( classlib ) and a server ( win service ).
the client sets up the remote object with type of the RemoteObject and it connects to the server.
The server has already setup a ChannelService and listens for incomming procedure calls to the remote object.
The remote object now returns some integer to the client.

But this is not what I want to do. I want the client to invoke a method from the server and pass it some parameter.
how do i adjust my code?

//client ( winform )
using System;
using System.Drawing;
using System.Collections;
using System.ComponentModel;
using System.Windows.Forms;
using System.Data;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Http;
using RemoteObject;


namespace RemoteClient
{
     /// <summary>
     /// Summary description for Form1.
     /// </summary>
     public class Form1 : System.Windows.Forms.Form
     {
          private System.Windows.Forms.Button button1;
          /// <summary>
          /// Required designer variable.
          /// </summary>
          private System.ComponentModel.Container components = null;

          public Form1()
          {
               //
               // Required for Windows Form Designer support
               //
               InitializeComponent();

               //
               // TODO: Add any constructor code after InitializeComponent call
               //
          }

          /// <summary>
          /// Clean up any resources being used.
          /// </summary>
          protected override void Dispose( bool disposing )
          {
               if( disposing )
               {
                    if (components != null)
                    {
                         components.Dispose();
                    }
               }
               base.Dispose( disposing );
          }

          #region Windows Form Designer generated code
          /// <summary>
          /// Required method for Designer support - do not modify
          /// the contents of this method with the code editor.
          /// </summary>
          private void InitializeComponent()
          {
               this.button1 = new System.Windows.Forms.Button();
               this.SuspendLayout();
               //
               // button1
               //
               this.button1.Location = new System.Drawing.Point(24, 24);
               this.button1.Name = "button1";
               this.button1.TabIndex = 0;
               this.button1.Text = "button1";
               this.button1.Click += new System.EventHandler(this.button1_Click);
               //
               // Form1
               //
               this.AutoScaleBaseSize = new System.Drawing.Size(5, 13);
               this.ClientSize = new System.Drawing.Size(292, 273);
               this.Controls.Add(this.button1);
               this.Name = "Form1";
               this.Text = "Form1";
               this.ResumeLayout(false);

          }
          #endregion

          /// <summary>
          /// The main entry point for the application.
          /// </summary>
          [STAThread]
          static void Main()
          {
               Application.Run(new Form1());
          }

          private void button1_Click(object sender, System.EventArgs e)
          {
               RemoteObject.IDGenerator remObject = (RemoteObject.IDGenerator)Activator.GetObject(
                    typeof(RemoteObject.IDGenerator),
                    "http://localhost:8085/RemotingServer"
                    );
               System.Windows.Forms.MessageBox.Show( Convert.ToString( remObject.getID() ) );
          }
     }
}


// Remote Object ( Class Library )
using System;

namespace RemoteObject
{
     public class IDGenerator : System.MarshalByRefObject
     {
          private int lastID = 0;
          public int getID()
          {
               return( lastID++ );
          }
     }
}

// Server ( windows service )
using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Diagnostics;
using System.ServiceProcess;
using System.Configuration.Install;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Http;
using System.Threading;

namespace RemoteService
{
     public class Service1 : System.ServiceProcess.ServiceBase
     {

          private System.ComponentModel.Container components = null;

          public Service1()
          {
               InitializeComponent();
          }
          static void Main()
          {
               System.ServiceProcess.ServiceBase[] ServicesToRun;
               ServicesToRun = new System.ServiceProcess.ServiceBase[] { new Service1() };
               System.ServiceProcess.ServiceBase.Run(ServicesToRun);
          }
          private void InitializeComponent()
          {
               components = new System.ComponentModel.Container();
               this.ServiceName = "Service1";
          }
          protected override void Dispose( bool disposing )
          {
               if( disposing )
               {
                    if (components != null)
                    {
                         components.Dispose();
                    }
               }
               base.Dispose( disposing );
          }
          Thread thdServer;
          protected override void OnStart(string[] args)
          {
               thdServer = new Thread( new ThreadStart( serverThread ) );
               thdServer.Start();
          }
          protected override void OnStop()
          {
               thdServer.Abort();
          }
          public void serverThread()
          {
               HttpChannel channel = new HttpChannel( 8085 );
               ChannelServices.RegisterChannel( channel );
               RemotingConfiguration.RegisterWellKnownServiceType(
                    typeof( RemoteObject.IDGenerator ),
                    "RemotingServer",
                    WellKnownObjectMode.Singleton
               );

          }
          // method that should be called from a client.
          public void DoSomething()
          {}
     }
}
0
Comment
Question by:DaFou
  • 4
  • 2
6 Comments
 
LVL 2

Author Comment

by:DaFou
ID: 11832307
preveralbly i do away with the whole remote object class library and setup a connection with some object in the service directly
0
 
LVL 7

Accepted Solution

by:
NipNFriar_Tuck earned 500 total points
ID: 11832488
Here is a sample project that I believe will help you...

http://www.bearcanyon.com/dotnet/#RemoteEvents
0
 
LVL 2

Author Comment

by:DaFou
ID: 11835801
i was too fast in accepting your answer :-(

I am unable to make the server component is such a way that it is a windows service. But i really need it to be a windows service.

please show me how to make it a service.
0
Announcing the Most Valuable Experts of 2016

MVEs are more concerned with the satisfaction of those they help than with the considerable points they can earn. They are the types of people you feel privileged to call colleagues. Join us in honoring this amazing group of Experts.

 
LVL 7

Expert Comment

by:NipNFriar_Tuck
ID: 11836141
Creating a service is not too far once you have an execuatable...

Here are the steps that I take...

1) If your server assembly is not a dll change it to be a dll.
2) Create a new C# Windows Service project in your solution... I called mine ProjService
3) Modify the class to start your application... There are plunty of comments in the class to help you here...
4) Open up in help ServiceProcessInstaller for complete directions to finish...

NOTE: You will want to do the installer, it makes things much easier...
0
 
LVL 2

Author Comment

by:DaFou
ID: 11836185
I have no clue what you mean..

please help out on this 500 points question
http://www.experts-exchange.com/Programming/Programming_Languages/C_Sharp/Q_21098923.html
0
 
LVL 2

Author Comment

by:DaFou
ID: 12003603
Hi NipNFriar_Tuck

http://www.experts-exchange.com/Programming/Programming_Languages/C_Sharp/Q_21116444.html
http://www.experts-exchange.com/Programming/Programming_Languages/C_Sharp/Q_21117316.html

Here are 2 identical ( yet asked different ) questions.
The latterone is near completion. If you could fix that one the other 500 points could be easily taken by copy pasting the solution of the latter in the first question.

I am sorry i have to flud EE with questions on remoting :-(

I hope you can help some more.
0

Featured Post

Gigs: Get Your Project Delivered by an Expert

Select from freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely and get projects done right.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Extention Methods in C# 3.0 by Ivo Stoykov C# 3.0 offers extension methods. They allow extending existing classes without changing the class's source code or relying on inheritance. These are static methods invoked as instance method. This…
Article by: Najam
Having new technologies does not mean they will completely replace old components.  Recently I had to create WCF that will be called by VB6 component.  Here I will describe what steps one should follow while doing so, please feel free to post any qu…
Along with being a a promotional video for my three-day Annielytics Dashboard Seminor, this Micro Tutorial is an intro to Google Analytics API data.
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…

813 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

11 Experts available now in Live!

Get 1:1 Help Now